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[SPAM] [obm-l] Re: EXPRESSOES:



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A proposito, tem essa: 1 + 2 =3D 0

"Demonstracao"

Considere a equacao x^2 + x + 1 =3D 0=C2=A0 -> x(x+1) =3D -1 (I)

Ainda da equacao original, temos x + 1 =3D -x^2 que substituida
em (I) nos fornece
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0=C2=A0=
=C2=A0-x^3 =3D - 1=C2=A0=C2=A0=C2=A0->=C2=A0 x =3D 1

Levando esse valor para a equacao original temos

=C2=A0 =C2=A0 =C2=A0 =C2=A0=C2=A0=C2=A01 + 1 + 1 =3D 0=C2=A0=C2=A0=C2=A0ou=
=C2=A0=C2=A0=C2=A01 + 2 =3D 0=C2=A0 "(CQD)"

> PS: esse problema me faz lembrar de algo importante:
>
> O fato obtermos um resultado verdadeiro ao "trabalharmos" uma
> expressao, nao torna necessariamente verdadeira a expressao original.
>
> E' fundamental que se possa fazer o caminho inverso, caso contrario,
> poderiamos "provar" que "-1=3D1"...
> Exemplo:
> Suponha que -x =3D x
> Obviamente isso e' valido para x=3D0.
> Mas se em vez de calcular o valor de x neste ponto, elevarmos os dois
> lados ao quadrado, obteriamos
> x^2 =3D x^2, que e' valido, por exemplo, para x=3D1.
> E assim, usando a expressao original, "provariamos" que -1=3D1.
>
> []'s
> Rogerio Ponce

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m email novo com a sua cara @ymail.com ou @rocketmail.com.=0Ahttp://br.new.=
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<table cellspacing=3D'0' cellpadding=3D'0' border=3D'0' ><tr><td valign=3D'=
top' style=3D'font: inherit;'><br>A proposito, tem essa: 1 + 2 =3D 0<br><br=
>"Demonstracao"<br><br>Considere a equacao x^2 + x + 1 =3D 0&nbsp; -&gt; x(=
x+1) =3D -1 (I)<br><br>Ainda da equacao original, temos x + 1 =3D -x^2 que =
substituida<br>em (I) nos fornece<br>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nb=
sp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp;-x^3 =3D - 1&nbsp;&nbsp;&nbsp;-&=
gt;&nbsp; x =3D 1<br><br>Levando esse valor para a equacao original temos<b=
r><br>&nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp;1 + 1 + 1 =3D 0&nbsp;&nbsp;&nb=
sp;ou&nbsp;&nbsp;&nbsp;1 + 2 =3D 0&nbsp; "(CQD)"<br><br><pre>&gt; PS: esse =
problema me faz lembrar de algo importante:<br>&gt;<br>&gt; O fato obtermos=
 um resultado verdadeiro ao "trabalharmos" uma<br>&gt; expressao, nao torna=
 necessariamente verdadeira a expressao original.<br>&gt;<br>&gt; E' fundam=
ental que se possa fazer o caminho inverso, caso contrario,<br>&gt; poderia=
mos "provar" que
 "-1=3D1"...<br>&gt; Exemplo:<br>&gt; Suponha que -x =3D x<br>&gt; Obviamen=
te isso e' valido para x=3D0.<br>&gt; Mas se em vez de calcular o valor de =
x neste ponto, elevarmos os dois<br>&gt; lados ao quadrado, obteriamos<br>&=
gt; x^2 =3D x^2, que e' valido, por exemplo, para x=3D1.<br>&gt; E assim, u=
sando a expressao original, "provariamos" que -1=3D1.<br>&gt;<br>&gt; []'s<=
br>&gt; Rogerio Ponce</pre><br><br></td></tr></table><br>=0A=0A=0A      <hr=
 size=3D1>Novos endere=C3=A7os, o Yahoo! que voc=C3=AA conhece. <a href=3D"=
http://br.rd.yahoo.com/mail/taglines/mail/*http://br.new.mail.yahoo.com/add=
resses">Crie um email novo</a> com a sua cara @ymail.com ou @rocketmail.com=
.
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