[SPAM] [obm-l] Res: [obm-l] Números algébricos

[Eduardo Estrada <eestradaitu@xxxxxxxxxxxx>]

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S=F3 um coment=E1rio/d=FAvida:=0A=0ASabe-se, por=E9m, que sen1 =E9 transcen=
dente (n=E3o sen(1=BA), mas sen(1rad)). Algu=E9m saberia responder, se =E9 =
que j=E1 foi encontrada uma resposta geral para essa pergunta, quando sen x=
 =E9 transcendente, para x, agora, natural e dado em radianos.=0A=0AUm abra=
=E7o,=0AEduardo=0A=0A----- Mensagem original ----=0ADe: Nicolau C. Saldanha=
 <nicolau.saldanha@xxxxxxxxx>=0APara: obm-l@xxxxxxxxxxxxxx=0AEnviadas: Ter=
=E7a-feira, 19 de Fevereiro de 2008 12:22:14=0AAssunto: Re: [obm-l] N=FAmer=
os alg=E9bricos=0A=0ATemos =0Aque =0Asen(x =0Agraus) =0A=E9 =0Aalg=E9brico =
=0Apara =0Atodo =0Ax =0Aracional.=0A=0ADe =0Afato, =0Az =0A=3D =0Aexp(2 =0A=
pi =0Ai =0Ap/q) =0A=E9 =0Aalg=E9brico =0Apara =0Aquaisquer =0Ainteiros =0Ap=
, =0Aq =0A(q =0A> =0A0)=0Apois =0Az =0Asatisfaz =0Aa =0Aequa=E7=E3o =0Az^q =
=0A=3D =0A1.=0AAnalogamente =0Ao =0Aconjugado =0Aconj(z) =0Ade =0Az =0Atamb=
=E9m =0A=E9 =0Aalg=E9brico.=0ATemos =0Aa =0A=3D =0Asen(2 =0Api =0Ap/q) =0A=
=3D =0A(z =0A- =0Aconj(z))/(2i).=0ASupondo =0Aque =0Avoc=EA =0Asaiba =0Aque=
 =0Aa =0Asoma =0Ae =0Ao =0Aproduto =0Ade =0An=FAmeros =0Aalg=E9bricos=0Atam=
b=E9m =0A=E9 =0Aalg=E9brico =0Atemos =0Aque =0Aa =0A=E9 =0Aalg=E9brico, =0A=
que =0A=E9 =0Ao =0Aque =0Avoc=EA =0Aqueria.=0A=0AN.=0A=0AOn =0AFeb =0A18, =
=0A2008 =0A8:22 =0APM, =0ACarlos =0AGomes =0A<cgmat@xxxxxxxxxxxxxx> =0Awrot=
e:=0A>=0A>=0A> =0AOl=E1 =0Aamigos...=0A>=0A>=0A> =0AQuais =0As=E3o =0Aos =
=0Avalores  =0Anaturais =0Ade =0Ax =0Apara =0Aos =0Aquais  =0Asenx=B0  =0A=
=E9 =0Aum =0An=FAmero=0A> =0Aalg=E9brico?=0A>=0A> =0ACgomes=0A>=0A=0A=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=0AInstru=E7=
=F5es =0Apara =0Aentrar =0Ana =0Alista, =0Asair =0Ada =0Alista =0Ae =0Ausar=
 =0Aa =0Alista =0Aem=0Ahttp://www.mat.puc-rio.br/~obmlistas/obm-l.html=0A=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=0A=0A=
=0A=0A=0A=0A=0A      Abra sua conta no Yahoo! Mail, o =FAnico sem limite de=
 espa=E7o para armazenamento!=0Ahttp://br.mail.yahoo.com/
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<html><head><style type=3D"text/css"><!-- DIV {margin:0px;} --></style></he=
ad><body><div style=3D"font-family:times new roman,new york,times,serif;fon=
t-size:12pt"><div style=3D"font-family: times new roman,new york,times,seri=
f; font-size: 12pt;">S=F3 um coment=E1rio/d=FAvida:<br><br>Sabe-se, por=E9m=
, que sen1 =E9 transcendente (n=E3o sen(1=BA), mas sen(1rad)). Algu=E9m sab=
eria responder, se =E9 que j=E1 foi encontrada uma resposta geral para essa=
 pergunta, quando sen x =E9 transcendente, para x, agora, natural e dado em=
 radianos.<br><br>Um abra=E7o,<br>Eduardo<br><br><div style=3D"font-family:=
 times new roman,new york,times,serif; font-size: 12pt;">----- Mensagem ori=
ginal ----<br>De: Nicolau C. Saldanha &lt;nicolau.saldanha@xxxxxxxxx&gt;<br=
>Para: obm-l@xxxxxxxxxxxxxx<br>Enviadas: Ter=E7a-feira, 19 de Fevereiro de =
2008 12:22:14<br>Assunto: Re: [obm-l] N=FAmeros alg=E9bricos<br><br>Temos =
=0Aque =0Asen(x =0Agraus) =0A=E9 =0Aalg=E9brico =0Apara =0Atodo =0Ax =0Arac=
ional.<br><br>De =0Afato, =0Az =0A=3D =0Aexp(2 =0Api =0Ai =0Ap/q) =0A=E9 =
=0Aalg=E9brico =0Apara =0Aquaisquer =0Ainteiros =0Ap, =0Aq =0A(q =0A&gt; =
=0A0)<br>pois =0Az =0Asatisfaz =0Aa =0Aequa=E7=E3o =0Az^q =0A=3D =0A1.<br>A=
nalogamente =0Ao =0Aconjugado =0Aconj(z) =0Ade =0Az =0Atamb=E9m =0A=E9 =0Aa=
lg=E9brico.<br>Temos =0Aa =0A=3D =0Asen(2 =0Api =0Ap/q) =0A=3D =0A(z =0A- =
=0Aconj(z))/(2i).<br>Supondo =0Aque =0Avoc=EA =0Asaiba =0Aque =0Aa =0Asoma =
=0Ae =0Ao =0Aproduto =0Ade =0An=FAmeros =0Aalg=E9bricos<br>tamb=E9m =0A=E9 =
=0Aalg=E9brico =0Atemos =0Aque =0Aa =0A=E9 =0Aalg=E9brico, =0Aque =0A=E9 =
=0Ao =0Aque =0Avoc=EA =0Aqueria.<br><br>N.<br><br>On =0AFeb =0A18, =0A2008 =
=0A8:22 =0APM, =0ACarlos =0AGomes =0A&lt;<a ymailto=3D"mailto:cgmat@digizap=
.com.br" href=3D"mailto:cgmat@xxxxxxxxxxxxxx";>cgmat@xxxxxxxxxxxxxx</a>&gt; =
=0Awrote:<br>&gt;<br>&gt;<br>&gt; =0AOl=E1 =0Aamigos...<br>&gt;<br>&gt;<br>=
&gt; =0AQuais =0As=E3o =0Aos =0Avalores&nbsp; =0Anaturais =0Ade =0Ax =0Apar=
a =0Aos =0Aquais&nbsp; =0Asenx=B0&nbsp; =0A=E9 =0Aum =0An=FAmero<br>&gt; =
=0Aalg=E9brico?<br>&gt;<br>&gt; =0ACgomes<br>&gt;<br><br>=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D<br>Instru=E7=F5es =0Apa=
ra =0Aentrar =0Ana =0Alista, =0Asair =0Ada =0Alista =0Ae =0Ausar =0Aa =0Ali=
sta =0Aem<br><a href=3D"http://www.mat.puc-rio.br/%7Eobmlistas/obm-l.html"; =
target=3D"_blank">http://www.mat.puc-rio.br/~obmlistas/obm-l.html</a><br>=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D<br></=
div><br></div></div><br>=0A=0A=0A      <hr size=3D1>Abra sua conta no <a hr=
ef=3D"http://br.rd.yahoo.com/mail/taglines/mail/*http://br.mail.yahoo.com/"=
>Yahoo! Mail</a>, o =FAnico sem limite de espa=E7o para armazenamento! =0A<=
/body></html>
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