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[SPAM] Re: [obm-l] Exercicio olimpico
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rust escreveu:
se p divide (a^29 - 1)/(a - 1), com p>29, ent=E3o p =3D=3D 1 mod 29 e =
para todo primo p =3D=3D 1 mod 29 existe pelo menos um a_p incongruente =
a 1 mod p tal que p divide [(a + lp)^29 - 1]/(a + lp - 1). Assim, pelo =
teorema do resto chin=EAs, podemos escolher um a tal que a =3D=3D a_p =
mod p_i, i =3D 1,2,3,...,n >=3D 2007
----- Original Message -----=20
From: Fernando Oliveira=20
To: obm-l@xxxxxxxxxxxxxx=20
Sent: Wednesday, December 05, 2007 10:03 AM
Subject: Re: [obm-l] Exercicio olimpico
Se algu=E9m souber ingl=EAs, pode tentar decifrar o que escreveram =
aqui: http://www.mathlinks.ro/viewtopic.php?t=3D173020
--=20
Fernando Oliveira
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charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2900.2722" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>rust escreveu:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>se p divide (a^29 - 1)/(a - 1), com =
p>29, ent=E3o=20
p =3D=3D 1 mod 29 e para todo primo p =3D=3D 1 mod 29 existe pelo menos =
um a_p=20
incongruente a 1 mod p tal que p divide [(a + lp)^29 - 1]/(a + lp - =
1).=20
Assim, pelo teorema do resto chin=EAs, podemos escolher um a tal que a =
=3D=3D a_p mod=20
p_i, i =3D 1,2,3,...,n >=3D 2007</FONT></DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A title=3Dfetofs@xxxxxxxxx href=3D"mailto:fetofs@xxxxxxxxx">Fernando =
Oliveira</A>=20
</DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@xxxxxxxxxxxxxx=20
href=3D"mailto:obm-l@xxxxxxxxxxxxxx">obm-l@xxxxxxxxxxxxxx</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Wednesday, December 05, =
2007 10:03=20
AM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> Re: [obm-l] Exercicio=20
olimpico</DIV>
<DIV><BR></DIV>Se algu=E9m souber ingl=EAs, pode tentar decifrar o que =
escreveram=20
aqui: <A=20
=
href=3D"http://www.mathlinks.ro/viewtopic.php?t=3D173020">http://www.math=
links.ro/viewtopic.php?t=3D173020</A><BR><BR>--=20
<BR>Fernando Oliveira </BLOCKQUOTE></BODY></HTML>
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