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[SPAM] RE: [obm-l] PA

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Subject: [SPAM] RE: [obm-l] PA
From: Vanessa Nunes de Souza <vanessanitcf@xxxxxxxxxxx>
Date: Sat, 24 May 2008 00:11:23 +0000
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 Desculpe, Thelio, na diferen=E7a dos termos, eu me enganei na diferan=E7a.=
 ao inv=E9s de=20
a32-a23  devemos ter a23-a32 o q nos d=E1 uma raz=E3o -7/9 e n=E3o 7/9 como=
 pensei, o restante =E9 s=F3 refazer os calculos com raz=E3o negativa, ou p=
ensar como o nosso amigo que fez pela soma dos termos equidistantes q ficou=
 bem mais f=E1cil.
=20
 vanessa nunes


From: vanessanitcf@xxxxxxxxxxxxx: obm-l@xxxxxxxxxxxxxxxxxxxxx: RE: [obm-l] =
PADate: Fri, 23 May 2008 20:17:09 +0000


 vamos l=E1, primeiro sabemos q a soma da PA =E9 1107 ent=E3o 1107=3D (a1 +=
 a54)27/2 ent=E3o   41 =3D a1+ a54  (1)tamb=E9m sabemos que a32 - a23 =3D 7=
   e a1+ 31r - a1 + 22r=3D 7  e 9r=3D 7 ent=E3o r=3D 7/9 pelo termio geral =
da PG temos que a54=3Da1+ 53r   logo a54=3D a1+ 477/9 (2) de  2 em 1 vem qu=
e: 41 =3D a1 + (a1 + 477/9) da=ED vem que a1=3D -6 logo  a23 =3D a1+ 22r =
=3D -6 + 22 . 7/9=3D 100/9  e a32=3D a1 + 31r =3D -6 + 31 . 7/9 =3D 163/9  =
espero ter ajudado.=20
 =20

Date: Fri, 23 May 2008 16:37:16 -0300From: teliogama@xxxxxxxxxxx: obm-l@mat=
.puc-rio.brSubject: [obm-l] PA
Boa tarde, professores,
=20
N=E3o consegui resolver esta PA:
=20
A soma dos 54 termos de uma PA =E9 1107. Determine o valor dos termos  a23 =
 e   a32  sabendo que a diferen=E7a entre eles =E9 igual a 7.
=20
Agrade=E7o a ajuda,
=20
Thelio
=20

Receba GR=C1TIS as mensagens do Messenger no seu celular quando voc=EA esti=
ver offline. Conhe=E7a o MSN Mobile! Crie j=E1 o seu!=20
_________________________________________________________________
Confira v=EDdeos com not=EDcias do NY Times, gols direto do Lance, videocas=
setadas e muito mais no MSN Video!
http://video.msn.com/?mkt=3Dpt-br=

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<head>
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margin:0px;
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<body class=3D'hmmessage'>
&nbsp;Desculpe, Thelio, na diferen=E7a dos termos, eu me enganei na diferan=
=E7a. ao inv=E9s de <BR>
a32-a23&nbsp; devemos ter a23-a32 o q nos d=E1 uma raz=E3o -7/9 e n=E3o 7/9=
 como pensei, o restante =E9 s=F3 refazer os calculos com raz=E3o negativa,=
 ou pensar como o nosso amigo que fez pela soma dos termos equidistantes q =
ficou bem mais f=E1cil.<BR>
&nbsp;<BR>
&nbsp;vanessa nunes<BR><BR><BR>
<BLOCKQUOTE>
<HR>
From: vanessanitcf@xxxxxxxxxxx<BR>To: obm-l@xxxxxxxxxxxxxx<BR>Subject: RE: =
[obm-l] PA<BR>Date: Fri, 23 May 2008 20:17:09 +0000<BR><BR>
<META content=3D"Microsoft SafeHTML" name=3DGenerator>
<STYLE>
.ExternalClass .EC_hmmessage P
{padding:0px;}
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&nbsp;vamos l=E1, primeiro sabemos q a soma da PA =E9 1107 ent=E3o 1107=3D =
(a1 + a54)27/2&nbsp;<BR>ent=E3o<BR>&nbsp;<BR>&nbsp;&nbsp;41 =3D a1+&nbsp;a5=
4&nbsp; (1)<BR><BR>tamb=E9m sabemos que a32 - a23 =3D 7&nbsp;&nbsp; e a1+ 3=
1r - a1 + 22r=3D 7&nbsp; e 9r=3D 7 ent=E3o r=3D 7/9<BR>&nbsp;<BR>pelo termi=
o geral da PG temos que a54=3Da1+ 53r&nbsp; <BR>&nbsp;<BR>logo a54=3D a1+ 4=
77/9 (2)<BR>&nbsp;<BR>de&nbsp; 2 em 1 vem que:<BR>&nbsp;<BR>41 =3D a1 + (a1=
 + 477/9) da=ED vem que a1=3D -6<BR>&nbsp;<BR>logo <BR>&nbsp;<BR>a23 =3D a1=
+ 22r =3D -6 + 22 . 7/9=3D 100/9&nbsp; e<BR>&nbsp;<BR>a32=3D&nbsp;a1 + 31r =
=3D -6 + 31 . 7/9 =3D 163/9<BR>&nbsp;<BR>&nbsp;espero ter ajudado.<BR>&nbsp=
;<BR>
<BLOCKQUOTE>&nbsp;<BR>&nbsp;<BR>
<HR>
<BR>Date: Fri, 23 May 2008 16:37:16 -0300<BR>From: teliogama@xxxxxxxxx<BR>T=
o: obm-l@xxxxxxxxxxxxxx<BR>Subject: [obm-l] PA<BR><BR><BR>
<DIV>Boa tarde, professores,</DIV>
<DIV>&nbsp;</DIV>
<DIV>N=E3o consegui resolver esta PA:</DIV>
<DIV>&nbsp;</DIV>
<DIV><SPAN style=3D"FONT-SIZE: 10pt; FONT-FAMILY: 'Times New Roman'"><FONT =
color=3D#000099><STRONG>A soma dos 54 termos de uma PA =E9 1107. Determine =
o valor dos termos &nbsp;a<SPAN style=3D"TOP: 5pt"><FONT size=3D1>23</FONT>=
</SPAN>&nbsp; e &nbsp;&nbsp;<FONT face=3D"Times New Roman">a<SPAN style=3D"=
TOP: 5pt"><FONT size=3D1>32</FONT></SPAN></FONT>&nbsp; sabendo que a difere=
n=E7a entre eles =E9 igual a 7.</STRONG></FONT></SPAN></DIV>
<DIV>&nbsp;</DIV>
<DIV>Agrade=E7o a ajuda,</DIV>
<DIV>&nbsp;</DIV>
<DIV>Thelio</DIV>
<DIV>&nbsp;</DIV></BLOCKQUOTE><BR>
<HR>
Receba GR=C1TIS as mensagens do Messenger no seu celular quando voc=EA esti=
ver offline. Conhe=E7a o MSN Mobile! <A href=3D"http://mobile.live.com/sign=
up/signup2.aspx?lc=3Dpt-br" target=3D_blank>Crie j=E1 o seu!</A> </BLOCKQUO=
TE><br /><hr />Not=EDcias direto do New York Times, gols do Lance, videocas=
setadas e muitos outros v=EDdeos no MSN Videos! <a href=3D'http://video.msn=
.com/?mkt=3Dpt-br' target=3D'_new'>Confira j=E1!</a></body>
</html>=

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References:
- [SPAM] [obm-l] PA
  - From: Thelio Gama
- [SPAM] RE: [obm-l] PA
  - From: Vanessa Nunes de Souza

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