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[SPAM] RE: [obm-l] PA
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vamos l=E1, primeiro sabemos q a soma da PA =E9 1107 ent=E3o 1107=3D (a1 +=
a54)27/2=20
ent=E3o
=20
41 =3D a1+ a54 (1)
tamb=E9m sabemos que a32 - a23 =3D 7 e a1+ 31r - a1 + 22r=3D 7 e 9r=3D 7=
ent=E3o r=3D 7/9
=20
pelo termio geral da PG temos que a54=3Da1+ 53r =20
=20
logo a54=3D a1+ 477/9 (2)
=20
de 2 em 1 vem que:
=20
41 =3D a1 + (a1 + 477/9) da=ED vem que a1=3D -6
=20
logo=20
=20
a23 =3D a1+ 22r =3D -6 + 22 . 7/9=3D 100/9 e
=20
a32=3D a1 + 31r =3D -6 + 31 . 7/9 =3D 163/9
=20
espero ter ajudado.
=20
=20
=20
Date: Fri, 23 May 2008 16:37:16 -0300From: teliogama@xxxxxxxxxxx: obm-l@mat=
.puc-rio.brSubject: [obm-l] PA
Boa tarde, professores,
=20
N=E3o consegui resolver esta PA:
=20
A soma dos 54 termos de uma PA =E9 1107. Determine o valor dos termos a23 =
e a32 sabendo que a diferen=E7a entre eles =E9 igual a 7.
=20
Agrade=E7o a ajuda,
=20
Thelio
=20
_________________________________________________________________
Receba GR=C1TIS as mensagens do Messenger no seu celular quando voc=EA esti=
ver offline. Conhe=E7a o MSN Mobile!
http://mobile.live.com/signup/signup2.aspx?lc=3Dpt-br=
--_c9711ea6-1db2-4977-83ce-eb1d215864e5_
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<html>
<head>
<style>
.hmmessage P
{
margin:0px;
padding:0px
}
body.hmmessage
{
FONT-SIZE: 10pt;
FONT-FAMILY:Tahoma
}
</style>
</head>
<body class=3D'hmmessage'>
vamos l=E1, primeiro sabemos q a soma da PA =E9 1107 ent=E3o 1107=3D =
(a1 + a54)27/2 <BR>
ent=E3o<BR>
<BR>
41 =3D a1+ a54 (1)<BR><BR>
tamb=E9m sabemos que a32 - a23 =3D 7 e a1+ 31r - a1 + 22r=3D 7&=
nbsp; e 9r=3D 7 ent=E3o r=3D 7/9<BR>
<BR>
pelo termio geral da PG temos que a54=3Da1+ 53r <BR>
<BR>
logo a54=3D a1+ 477/9 (2)<BR>
<BR>
de 2 em 1 vem que:<BR>
<BR>
41 =3D a1 + (a1 + 477/9) da=ED vem que a1=3D -6<BR>
<BR>
logo <BR>
<BR>
a23 =3D a1+ 22r =3D -6 + 22 . 7/9=3D 100/9 e<BR>
<BR>
a32=3D a1 + 31r =3D -6 + 31 . 7/9 =3D 163/9<BR>
<BR>
espero ter ajudado.<BR>
<BR>
<BLOCKQUOTE>
<BR>
<BR>
<HR>
<BR>
Date: Fri, 23 May 2008 16:37:16 -0300<BR>From: teliogama@xxxxxxxxx<BR>To: o=
bm-l@xxxxxxxxxxxxxx<BR>Subject: [obm-l] PA<BR><BR><BR>
<DIV>Boa tarde, professores,</DIV>
<DIV> </DIV>
<DIV>N=E3o consegui resolver esta PA:</DIV>
<DIV> </DIV>
<DIV><SPAN style=3D"FONT-SIZE: 10pt; FONT-FAMILY: 'Times New Roman'"><FONT =
color=3D#000099><STRONG>A soma dos 54 termos de uma PA =E9 1107. Determine =
o valor dos termos a<SPAN style=3D"TOP: 5pt"><FONT size=3D1>23</FONT>=
</SPAN> e <FONT face=3D"Times New Roman">a<SPAN style=3D"=
TOP: 5pt"><FONT size=3D1>32</FONT></SPAN></FONT> sabendo que a difere=
n=E7a entre eles =E9 igual a 7.</STRONG></FONT></SPAN></DIV>
<DIV> </DIV>
<DIV>Agrade=E7o a ajuda,</DIV>
<DIV> </DIV>
<DIV>Thelio</DIV>
<DIV> </DIV></BLOCKQUOTE><br /><hr />Receba GR=C1TIS as mensagens do M=
essenger no seu celular quando voc=EA estiver offline. Conhe=E7a o MSN Mob=
ile! <a href=3D'http://mobile.live.com/signup/signup2.aspx?lc=3Dpt-br' targ=
et=3D'_new'>Crie j=E1 o seu!</a></body>
</html>=
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