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[SPAM] [obm-l] Re: [obm-l] POLINÔMIO
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Correto.
Fatorando, obtemos p(x) = (x^2 + 1)(x + 1)
Daí, x^2 + 1 = 0 => a = +i e b = -i
Segue que a^2 + b^2 = i^2 + (-i)^2 = -2
[ ]´s
Angelo
--- Em qua, 30/4/08, arkon <arkon@xxxxxxxxxx> escreveu:
> De: arkon <arkon@xxxxxxxxxx>
> Assunto: [obm-l] POLINÔMIO
> Para: "obm-l" <obm-l@xxxxxxxxxxxxxx>
> Data: Quarta-feira, 30 de Abril de 2008, 9:28
> Pessoal, uma de polinômio
>
> (UNB) No polinômio p(x) = x^3 + x^2 + x + 1, uma das
> raízes é x = -1. Então, se a e b forem as outras
> raízes, tem-se que a^2 + b^2 = -2 ?
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