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[SPAM] [obm-l] Re: [obm-l] função contínua

To: <obm-l@xxxxxxxxxxxxxx>
Subject: [SPAM] [obm-l] Re: [obm-l] função contínua
From: "Carlos Gomes" <cgmat@xxxxxxxxxxxxxx>
Date: Mon, 11 Feb 2008 16:01:03 -0300
References: <E4C89EA639092445A78832509143CCB81695568566@xxxxxxxxxxxxxxxx>
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Artur, note que f(a)=3Da e f(b)=3Db , como a<b segue que f(a)<f(b). =
Assim f n=E3o pode ser estritamente decrescente, n=E3o acha? Quanto ao =
enunciado =E9 esse mesmo. Esta quest=E3o est=E1 na p=E1g 107 ( quest=E3o =
19) do livro ADVANCED CALCULUS=20
Autor: Angus E. Taylor

valew

Cgomes
  ----- Original Message -----=20
  From: Artur Costa Steiner=20
  To: obm-l@xxxxxxxxxxxxxx=20
  Sent: Monday, February 11, 2008 2:50 PM
  Subject: RES: [obm-l] fun=E7=E3o cont=EDnua


  Da forma como est=E1 colocada, a afirma=E7=E3o n=E3o =E9 verdadeira.=20

  Se f for estritamente decrescente, ent=E3o f' eh sempre negativa em =
(a, b) e n=E3o ha como a sua express=E3o dar 2, pois =E9 sempre =
negativa.=20

  Nao estah faltando aguma hipotese?
  Artur
    -----Mensagem original-----
    De: owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx]Em =
nome de Carlos Gomes
    Enviada em: domingo, 10 de fevereiro de 2008 09:42
    Para: obm-l@xxxxxxxxxxxxxx
    Assunto: [obm-l] fun=E7=E3o cont=EDnua



    ----- Original Message -----=20
    From: Carlos Gomes=20
    To: obm-l@xxxxxxxxxxxxxx=20
    Sent: Saturday, February 09, 2008 7:45 AM
    Subject: fun=E7=E3o cont=EDnua


    Ol=E1 amigos...ser=E1 que algu=E9m pode me ajudar com essa?

    Seja f uma fun=E7=E3o cont=EDnua em [a,b] e diferenci=E1vel em (a,b) =
tal que f(a)=3Da e f(b)=3Db. Mostre que existem x_1 e x_2 tais que a< =
x_1 < x_2 < b tais que 1/f ' (x_1)  +  1/f ' (x_2) =3D 2.


    Valew, Cgomes


  __________ Informa=E7=E3o do NOD32 IMON 1.1189 (20050808) __________

  Esta mensagem foi verificada pelo NOD32 sistema antiv=EDrus
  http://www.eset.com.br

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2900.2722" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Artur, note que f(a)=3Da e f(b)=3Db , =
como a&lt;b segue=20
que f(a)&lt;f(b). Assim f n=E3o pode ser estritamente decrescente, n=E3o =
acha?=20
Quanto ao enunciado =E9 esse mesmo. Esta quest=E3o est=E1 na p=E1g 107 ( =
quest=E3o 19) do=20
livro ADVANCED CALCULUS </FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Autor: Angus E. Taylor</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>valew</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>Cgomes</FONT></DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  <DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV=20
  style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
  <A title=3Dartur.steiner@xxxxxxxxxx =
href=3D"mailto:artur.steiner@xxxxxxxxxx";>Artur=20
  Costa Steiner</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@xxxxxxxxxxxxxx=20
  href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Monday, February 11, 2008 =
2:50=20
  PM</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Subject:</B> RES: [obm-l] =
fun=E7=E3o=20
  cont=EDnua</DIV>
  <DIV><BR></DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff size=3D2>Da=20
  forma como est=E1 colocada, a afirma=E7=E3o n=E3o =E9 verdadeira. =
</FONT></SPAN></DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff=20
  size=3D2></FONT></SPAN>&nbsp;</DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff size=3D2>Se f=20
  for estritamente decrescente, ent=E3o f' eh sempre negativa em (a, b) =
e n=E3o=20
  ha&nbsp;como a&nbsp;sua express=E3o dar&nbsp;2, pois =E9 sempre =
negativa.=20
  </FONT></SPAN></DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff=20
  size=3D2></FONT></SPAN>&nbsp;</DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff size=3D2>Nao=20
  estah faltando aguma hipotese?</FONT></SPAN></DIV>
  <DIV><SPAN class=3D685574617-11022008><FONT face=3DArial =
color=3D#0000ff=20
  size=3D2>Artur</FONT></SPAN></DIV>
  <BLOCKQUOTE dir=3Dltr style=3D"MARGIN-RIGHT: 0px">
    <DIV class=3DOutlookMessageHeader dir=3Dltr align=3Dleft><FONT =
face=3DTahoma=20
    size=3D2>-----Mensagem original-----<BR><B>De:</B> <A=20
    =
href=3D"mailto:owner-obm-l@xxxxxxxxxxxxxx";>owner-obm-l@xxxxxxxxxxxxxx</A>=
=20
    [mailto:owner-obm-l@xxxxxxxxxxxxxx]<B>Em nome de </B>Carlos=20
    Gomes<BR><B>Enviada em:</B> domingo, 10 de fevereiro de 2008=20
    09:42<BR><B>Para:</B> obm-l@xxxxxxxxxxxxxx<BR><B>Assunto:</B> =
[obm-l] fun=E7=E3o=20
    cont=EDnua<BR><BR></FONT></DIV>
    <DIV>&nbsp;</DIV>
    <DIV style=3D"FONT: 10pt arial">----- Original Message -----=20
    <DIV style=3D"BACKGROUND: #e4e4e4; font-color: black"><B>From:</B> =
<A=20
    title=3Dcgmat@xxxxxxxxxxxxxx =
href=3D"mailto:cgmat@xxxxxxxxxxxxxx";>Carlos=20
    Gomes</A> </DIV>
    <DIV><B>To:</B> <A title=3Dobm-l@xxxxxxxxxxxxxx=20
    href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A> </DIV>
    <DIV><B>Sent:</B> Saturday, February 09, 2008 7:45 AM</DIV>
    <DIV><B>Subject:</B> fun=E7=E3o cont=EDnua</DIV></DIV>
    <DIV><BR></DIV>
    <DIV><FONT face=3DArial size=3D2>Ol=E1 amigos...ser=E1 que algu=E9m =
pode me ajudar com=20
    essa?</FONT></DIV>
    <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
    <DIV><FONT face=3DArial size=3D2>Seja f uma fun=E7=E3o cont=EDnua em =
[a,b] e=20
    diferenci=E1vel em (a,b) tal que f(a)=3Da e f(b)=3Db. Mostre que =
existem x_1 e x_2=20
    tais que a&lt; x_1 &lt; x_2 &lt; b tais que 1/f ' (x_1)&nbsp; =
+&nbsp; 1/f '=20
    (x_2) =3D 2.</FONT></DIV>
    <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
    <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
    <DIV><FONT face=3DArial size=3D2>Valew,=20
  Cgomes</FONT></DIV></BLOCKQUOTE><BR><BR>__________ Informa=E7=E3o do =
NOD32 IMON=20
  1.1189 (20050808) __________<BR><BR>Esta mensagem foi verificada pelo =
NOD32=20
  sistema antiv=EDrus<BR><A=20
  =
href=3D"http://www.eset.com.br";>http://www.eset.com.br</A><BR></BLOCKQUOT=
E></BODY></HTML>

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- RES: [obm-l] Re: [obm-l] função contínua
  - From: Artur Costa Steiner
- [SPAM] Re: [obm-l] função contínua
  - From: Artur Costa Steiner
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  - From: Artur Costa Steiner

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- RES: [obm-l] função contínua
  - From: Artur Costa Steiner

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