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[SPAM] [obm-l] Probabilidade
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Esta é uma mensagem em várias partes no formato MIME.
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Boa Tarde pessoal da lista, a minha d=FAvida e a seguinte eu fiz esse
exerc=EDcio usando arranjo nos c=E1lculos de probabilidade, porem o meu
professor me deu errado na prova, mas as respostas finas foram as mesma. =
Eu
queria saber se ta errado o que fiz..
=20
Meus c=E1lculos:
=20
P(3 mulheres)=3D A(4,3) / A(10,3) =3D 1/30
=20
P(2 ao menos sendo mulheres) =3D A(4,2)*A(6,1)/ A(10,3) =3D 1/10 + 1/30 =
=3D 1/15
=20
=20
Resposta do gabarito=20
P(3 mulheres)=3D C(4,3) / C(10,3) =3D 1/30
=20
P(2 ao menos sendo mulheres) =3D C(4,3) / C(10,3) + {C(4,2) / C(10,3)} =
* 6 =3D
1/10 + 1/30 =3D 1/15
=20
=20
=20
Um grupo e constitu=EDdo de seis homens e quatro mulheres. Tr=EAs =
pessoas s=E3o
selecionadas ao acaso, neste grupo, sem reposi=E7=E3o, e os seguintes =
eventos
s=E3o considerados: as tr=EAs pessoas s=E3o mulheres; ao menos duas =
pessoas s=E3o
mulheres.
=20
Calcule a probabilidade de cada um dos eventos definidos ocorrerem.
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<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>Boa Tarde pessoal da lista, a minha d=FAvida e a =
seguinte eu
fiz esse exerc=EDcio usando arranjo nos c=E1lculos de probabilidade, =
porem o meu=A0
professor me deu errado na prova, mas as respostas finas foram as mesma. =
Eu
queria saber se ta errado o que fiz..<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>Meus c=E1lculos:<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>P(3 mulheres)=3D A(4,3) / A(10,3) =3D =
1/30<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>P(2 ao menos sendo mulheres) =3D A(4,2)*A(6,1)/ =
A(10,3) =3D 1/10
+ 1/30 =3D 1/15<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
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style=3D'font-size:10.0pt;
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<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>Resposta do gabarito <o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>P(3 mulheres)=3D C(4,3) / C(10,3) =3D =
1/30<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>P(2 ao menos sendo mulheres) =3D C(4,3) / C(10,3) + =
=A0{C(4,2) /
C(10,3)} * 6 =A0=3D 1/10 + 1/30 =3D 1/15<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
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<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>Um grupo e constitu=EDdo de seis homens e quatro =
mulheres. Tr=EAs
pessoas s=E3o selecionadas ao acaso, neste grupo, sem reposi=E7=E3o, e =
os seguintes
eventos s=E3o considerados: as tr=EAs pessoas s=E3o mulheres; ao menos =
duas pessoas s=E3o
mulheres.<o:p></o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'><o:p> </o:p></span></p>
<p class=3DMsoNormal style=3D'text-autospace:none'><span =
style=3D'font-size:10.0pt;
font-family:CMR10'>Calcule a probabilidade de cada um dos eventos =
definidos
ocorrerem.</span><o:p></o:p></p>
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