[obm-l] CONTINUIDADE

To: obm-l@xxxxxxxxxxxxxx
Subject: [obm-l] CONTINUIDADE
From: Klaus Ferraz <klausferraz@xxxxxxxxxxxx>
Date: Sun, 20 May 2007 10:13:40 -0700 (PDT)
DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com.br; h=X-YMail-OSG:Received:X-Mailer:Date:From:Subject:To:MIME-Version:Content-Type:Message-ID; b=b2jOZzjrNQnSUy3dz6EeMNe+rU+MP9vrhKg3tkhwCQctTE5k9FYlnu4Jm92pkXEf2CZr+ea3DAxxCVyQtSqfX/YBC9xeu4yAKHPL8a7tAGfiOIeDxqoHtSQr0N94vRHfoifiuvqjkIkEKJIkNRZxQ8rBrqNjxqB6cN3eNXTTbnU=;
Reply-To: obm-l@xxxxxxxxxxxxxx
Sender: owner-obm-l@xxxxxxxxxxxxxx

Seja f:[0,1]->[0,1] crescente (x<y => f(x)<ou= f(y)), mas não
necessariamente contínua. Mostre que existe x em [0,1] tal que f(x)=x.
vlw.

__________________________________________________
Fale com seus amigos de graça com o novo Yahoo! Messenger
http://br.messenger.yahoo.com/