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Re: [obm-l] Alguém ajuda?
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Alguém ajuda?
- From: ricardo.bioni@xxxxxxxxx
- Date: Mon, 12 Jun 2006 13:08:06 -0300
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Essa soma é igual a [(0 + 2 + 3 + ... + 9)*10^2 + 11] + [(0 + 2 + 3 +
... + 9)*10 + 101] + [(0 + 2 + 3 + ... + 9) + 110] = (4400 + 11) + (440
+ 101) + (44 + 110) = 4884 + 222 = 5106.