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[obm-l] Trigonometria(dificil!!!)
- To: obm-l@xxxxxxxxxxxxxx
- Subject: [obm-l] Trigonometria(dificil!!!)
- From: vinicius aleixo <viniciusaleixo@xxxxxxxxxxxx>
- Date: Tue, 7 Feb 2006 22:04:57 -0300 (ART)
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olá,
Sabemos que a(senx)(seny) + b(cosx)(cosy)=0
Z = 1/[a(senx)^2+b(cosx)^2] + 1/[a(seny)^2+b(cosy)^2]
mostre q Z independe de x e y.
abraços,
Vinícius Meireles Aleixo
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