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Re: [obm-l] Expressao !! facil !!!
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Em Thursday 24 July 2003 11:42, Rodrigo Salcedo escreveu:
> [...]
> Calcule a expressao
> Y=[ sen ( pi - arcsen a) + cos( pi/2 + arcsenb)] / [ cos (3pi/2 + arcsen a)
> + sen(pi/2 - arccos b)
> [...]
sen(pi-x) = sen x
cos(pi/2+x) = -cos(pi/2-x) = -sen(x)
cos(3pi/2+x) = cos(x-pi/2) = cos(pi/2-x) = sen(x)
sen(pi/2-x) = cos(x)
Logo a expressão vale
[sen(arcsen(a)) - sen(arcsen(b))]/[sen(arcsen(a)) + cos(arccos(b))] =
(a-b)/(a+b).
[]s,
- --
Fábio "ctg \pi" Dias Moreira
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