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Re: [obm-l] trigonometria



6x/pi = 1 =>x=pi/6 =>3x=pi/2 =>cos(pi/2) = 0
----- Original Message -----
Sent: Thursday, January 02, 2003 7:15 PM
Subject: [obm-l] trigonometria

Porque se a tg  (9pi/4)=6x/pi, então cos 3x é zero?