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Re: [obm-l] trigonometria

To: <obm-l@xxxxxxxxxxxxxx>
Subject: Re: [obm-l] trigonometria
From: "larryp" <larryp@xxxxxxxxxx>
Date: Fri, 3 Jan 2003 09:44:09 -0200
References: <14.6292adf.2b4605d8@aol.com>
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tg(9pi/4) = tg(pi/4) = 1 = 6x / pi ==> x = pi/6 ==> 3x = pi/2 ==> cos 3x = cos(pi/2) = 0.

----- Original Message -----

From: Faelccmm@aol.com

To: obm-l@mat.puc-rio.br

Sent: Thursday, January 02, 2003 7:15 PM

Subject: [obm-l] trigonometria

Porque se a tg (9pi/4)=6x/pi, então cos 3x é zero?

References:
- [obm-l] trigonometria
  - From: Faelccmm

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