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[SPAM] Re: [obm-l] outra de sequencia

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Suponho que h =E9 uma constante que deixa sqrt(n + h) com sentido, isto =
=E9 n+h > 0 para n=3D1,2,3,4,......
Assim sendo temos:
[sqrt(n+h) + sqrt(n)].[sqrt(n+h) - sqrt(n)]=3Dh, da=ED temos:

[sqrt(n+h) - sqrt(n)]=3D h/ [sqrt(n+h) + sqrt(n)] e, essa fra=E7=E3o, =
certamente tende a zero quando n tende a + infinito.

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<META http-equiv=3DContent-Type content=3D"text/html; =
<META content=3D"MSHTML 6.00.2600.0" name=3DGENERATOR>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Suponho que h =E9 uma constante que =
deixa sqrt(n + h)=20
com sentido, isto =E9 n+h &gt; 0 para n=3D1,2,3,4,......</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Assim sendo temos:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>[sqrt(n+h) + sqrt(n)].[sqrt(n+h) - =
sqrt(n)]=3Dh, da=ED=20
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>[sqrt(n+h) - sqrt(n)]=3D h/ [sqrt(n+h) =
+ sqrt(n)] e,=20
essa fra=E7=E3o, certamente tende a zero quando n tende a + =
<DIV><FONT face=3DArial size=3D2>Certo?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Arconcher</FONT></DIV></BODY></HTML>


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