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[SPAM] Re: [obm-l] outra de sequencia
- To: obm-l@xxxxxxxxxxxxxx
- Subject: [SPAM] Re: [obm-l] outra de sequencia
- From: "Gustavo Simoes Araujo" <gustavo.simoes1@xxxxxxxxx>
- Date: Fri, 13 Jun 2008 16:43:25 +0200
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Ola Luciana,
Ent=E3o acho que voc=EA pode resolver esta quest=E3o desta maneira:
a_n=3D sqrt(n+h) - sqrt(n) =3D ( sqrt(n+h) - sqrt(n) ) * (sqrt(n+h) + sqrt=
(n)
)/ (sqrt(n+h) + sqrt(n) )
a_n=3D ( (n+h) - n )/ (sqrt(n+h) + sqrt(n) ) =3D h / (sqrt(n+h) + sqrt(n)=
)
tendendo este limite para zero quando n tende para o infinito.
Abra=E7os,
--=20
Gustavo Sim=F5es Ara=FAjo
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<div>Ola Luciana,</div>
<div> </div>
<div> Ent=E3o acho que voc=EA pod=
e resolver esta quest=E3o desta maneira:</div>
<div> </div>
<div>a_n=3D sqrt(n+h) - sqrt(n) =3D ( sqrt(n+h) - sqrt(n) ) * (sqrt(n=
+h) + sqrt(n) )/ (sqrt(n+h) + sqrt(n) )</div>
<div> </div>
<div>a_n=3D ( (n+h) - n )/ (sqrt(n+h) + sqrt(n) ) =3D h /&n=
bsp; (sqrt(n+h) + sqrt(n) ) tendendo este limite para zero quando=
n tende para o infinito.</div>
<div> </div>
<div>Abra=E7os,</div>
<div> </div><br>-- <br>Gustavo Sim=F5es Ara=FAjo=20
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