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[SPAM] Re: [obm-l] PG
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Numa PG, a_n =3D a_1 * q^(n-1).
Assim,
y =3D xq^(2n) e z =3D xq^(3n), e, deste modo, y^3 =3D xz^2.
Um abra=E7o,
Jo=E3o Lu=EDs
----- Original Message -----=20
From: Rejane=20
To: obm-l@xxxxxxxxxxxxxx=20
Sent: Thursday, May 29, 2008 12:11 PM
Subject: [obm-l] PG
Boa tarde,
algu=E9m poderia me mostrar como se resolve?
Obrigada.
(fatec 97) Se, em uma progress=E3o geom=E9trica, x =E9 o primeiro =
termo, y =E9 o termo de ordem 2n+1, e z =E9 o termo de ordem 3n+1, =
ent=E3o =E9 verdade que:
a) z=B3 =3D yx=B2
b) x=B3 =3D yz=B2
c) x=B3 =3D zy=B2
d) y=B3 =3D xz=B2
e) y=B3 =3D zx=B2
Resposta: letra d
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charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.6000.16640" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT size=3D2>Numa PG, a_n =3D a_1 * q^(n-1).</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Assim,</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>y =3D xq^(2n) e z =3D xq^(3n), e, deste modo, y^3 =
=3D=20
xz^2.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Um abra=E7o,</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Jo=E3o Lu=EDs</FONT></DIV>
<BLOCKQUOTE dir=3Dltr=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A title=3Drejane@xxxxxxxxxxx =
href=3D"mailto:rejane@xxxxxxxxxxx";>Rejane</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@xxxxxxxxxxxxxx=20
href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Thursday, May 29, 2008 =
12:11=20
PM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> [obm-l] PG</DIV>
<DIV><BR></DIV>
<DIV><FONT face=3DArial size=3D4>Boa tarde,</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>algu=E9m poderia me mostrar como se=20
resolve?</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>Obrigada.</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>(fatec 97) Se, em uma progress=E3o =
geom=E9trica, x =E9=20
o primeiro termo, y =E9 o termo de ordem 2n+1, e z =E9 o termo de =
ordem 3n+1,=20
ent=E3o =E9 verdade que:</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>a) z=B3 =3D yx=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>b) x=B3 =3D yz=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>c) x=B3 =3D zy=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>d) y=B3 =3D xz=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>e) y=B3 =3D zx=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>Resposta: letra=20
d</FONT></DIV></BLOCKQUOTE></BODY></HTML>
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