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[SPAM] [obm-l] PG
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This is a multi-part message in MIME format.
------=_NextPart_000_018C_01C8C185.3121D0D0
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
Boa tarde,
algu=E9m poderia me mostrar como se resolve?
Obrigada.
(fatec 97) Se, em uma progress=E3o geom=E9trica, x =E9 o primeiro termo, =
y =E9 o termo de ordem 2n+1, e z =E9 o termo de ordem 3n+1, ent=E3o =E9 =
verdade que:
a) z=B3 =3D yx=B2
b) x=B3 =3D yz=B2
c) x=B3 =3D zy=B2
d) y=B3 =3D xz=B2
e) y=B3 =3D zx=B2
Resposta: letra d
------=_NextPart_000_018C_01C8C185.3121D0D0
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2900.3243" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D4>Boa tarde,</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>algu=E9m poderia me mostrar como se=20
resolve?</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>Obrigada.</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>(fatec 97) Se, em uma progress=E3o =
geom=E9trica, x =E9 o=20
primeiro termo, y =E9 o termo de ordem 2n+1, e z =E9 o termo de ordem =
3n+1, ent=E3o =E9=20
verdade que:</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>a) z=B3 =3D yx=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>b) x=B3 =3D yz=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>c) x=B3 =3D zy=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>d) y=B3 =3D xz=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4>e) y=B3 =3D zx=B2</FONT></DIV>
<DIV><FONT face=3DArial size=3D4></FONT> </DIV>
<DIV><FONT face=3DArial size=3D4>Resposta: letra =
d</FONT></DIV></BODY></HTML>
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