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[SPAM] Re: [obm-l] Inequação



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Obrigado pela resposta.

> Estudo dos módulos:
>     1. x<=-1
>        |x+1|=-(x+1) e |x|=-x
>       Logo
>       3|x+1| +| x| < 1 => -3(x+1)-x<1 => -4x<4 => x>-1   (I)
> 
>     2. -1<x<=0
>        |x+1|=x+1 e |x|=-x
>       Logo
>       3|x+1| +| x| < 1 => 3(x+1)-x<1 => 2x<-2 => x<-1   (II)
> 
>     3. x>0
>        |x+1|=x+1 e |x|=x
>       Logo
>       3|x+1| +| x| < 1 => 3(x+1)+x<1 => 4x<-2 => x<-1/2   (III)
> 
>    Solução: vazio.
> 
> 
> 
> 
> Citando rack@xxxxxxxxxxx:
> 
> > olá,
> >
> > alguém poderia me ajudar com essa inequação...
> >
> > Obrigado
> >
> > 3|x+1| +| x| < 1
> > ========================================================================> Instruções para entrar
> > na lista, sair da lista e usar a lista em http://www.mat.puc-rio.br/~obmlistas/obm-l.html
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> 
> 
> 
> -- 
> Arlane Manoel S Silva
>    MAT-IME-USP
> 
> 
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