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[SPAM] Re: [obm-l] SigmaDelta

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Ol=E1 lista, considerando a import=E2ncia que tem para mim a =
resolu=E7=E3o desta quest=E3o, estou reformulando a pergunta na =
esperan=E7a de que alguem se interesse por ela.

Mostrar que a m=E9dia aritim=E9tica dos valores gerador pela sequencia: =
D(1), D(2)....D(n) converge para V quando R > |V|

onde D(n) =3D R * I(n) / |I(n)|,=20

e I(n) =3D I(n-1) + V - D(n-1),

com: D(0) =3D I(0) =3D 0

R e V reais com R > 0

Ojesed.



  ----- Original Message -----=20
  From: Ojesed Mirror=20
  To: obm-l@xxxxxxxxxxxxxx=20
  Sent: Friday, March 14, 2008 2:43 PM
  Subject: [obm-l] SigmaDelta


  Ol=E1 lista, pe=E7o ajuda, n=E3o achei uma sa=EDda anal=EDtica.

  A(n) =3D A(n-1) + ( D(n) - A(n-1) )/n

  onde:

  D(n) =3D sinal( I(n) )*R=20
  e
  I(n) =3D I(n-1) + V - D(n-1)

  Mostrar que A(n) converge para V quando |V| < R

  Considerar:=20
  A(0) =3D D(0) =3D I(0) =3D 0.
  n inteiro, R constante real positiva, V constante real.
  sinal() retorna 1 para argumento positivo, -1 para argumento negativo =
e 0 para argumento nulo.


  Obrigado, Ojesed.
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML xmlns:o =3D "urn:schemas-microsoft-com:office:office" xmlns:st1 =
=3D=20
"urn:schemas-microsoft-com:office:smarttags"><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.6000.16609" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Ol=E1 lista, considerando a =
import=E2ncia que tem para=20
mim a resolu=E7=E3o desta quest=E3o, estou&nbsp;reformulando a pergunta =
na esperan=E7a=20
de que alguem se interesse por ela.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>Mostrar que a m=E9dia aritim=E9tica dos =
valores gerador=20
pela sequencia: D(1), D(2)....D(n) converge para V quando R &gt;=20
|V|</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>onde </FONT><FONT face=3DArial =
size=3D2>D(n) =3D&nbsp;R *=20
I(n) / |I(n)|, </FONT></DIV>
<DIV>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>e I(n) =3D I(n-1) + V - =
D(n-1),</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>com: D(0) =3D I(0) =3D 0</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>R e V reais com R &gt; 0</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2>Ojesed.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
<BLOCKQUOTE dir=3Dltr=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  <DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV=20
  style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
  <A title=3Dojesed@xxxxxxxxxx href=3D"mailto:ojesed@xxxxxxxxxx";>Ojesed =
Mirror</A>=20
  </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@xxxxxxxxxxxxxx=20
  href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Friday, March 14, 2008 =
2:43=20
PM</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Subject:</B> [obm-l] =
SigmaDelta</DIV>
  <DIV><BR></DIV>
  <DIV><FONT face=3DArial size=3D2>Ol=E1 lista, pe=E7o ajuda, n=E3o =
achei uma sa=EDda=20
  anal=EDtica.</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>A(n) =3D A(n-1) + ( D(n) - A(n-1) =
)/n</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>onde:</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>D(n) =3D sinal( I(n) )*R =
</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2>e</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2>I(n) =3D I(n-1) + V - =
D(n-1)</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Mostrar&nbsp;que A(n) converge para V =
quando |V|=20
  &lt; R</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Considerar: </FONT></DIV>
  <DIV><FONT face=3DArial size=3D2>A(0) =3D D(0) =3D I(0) =3D =
0.</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2>n inteiro, R constante real positiva, =
V constante=20
  real.</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2>sinal() retorna 1 para argumento =
positivo, -1=20
  para argumento negativo e 0 para argumento nulo.</FONT></DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2></FONT>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Obrigado,=20
Ojesed.</FONT></DIV></BLOCKQUOTE></BODY></HTML>

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