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Re: [obm-l] ALTURA DO TETRAEDRO
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] ALTURA DO TETRAEDRO
- From: "Marcos Martinelli" <mffmartinelli@xxxxxxxxx>
- Date: Tue, 4 Mar 2008 13:58:04 -0300
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A projeção do vértice deve coincidir com o circuncentro do triângulo
da base. Devemos calcular o raio desse círculo.
S = a * b * c / ( 4 * R ) -> 6 * 8 / 2 = 6 * 8 * 10 / ( 4 * R ) -> R = 5.
Portanto, a altura é um cateto de um triângulo retângulo de hipotenusa
13 e outro cateto 5. Logo, a altura vale 12.
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