[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
[SPAM] [obm-l] Res: [obm-l] Provar que é quadrado perfeito
- To: obm-l@xxxxxxxxxxxxxx
- Subject: [SPAM] [obm-l] Res: [obm-l] Provar que é quadrado perfeito
- From: Danilo Nascimento <souza_danilo@xxxxxxxxxxxx>
- Date: Sat, 23 Feb 2008 19:08:39 -0800 (PST)
- Domainkey-signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com.br; h=X-YMail-OSG:Received:X-Mailer:Date:From:Subject:To:MIME-Version:Content-Type:Message-ID; b=T1hAkAKfCBCmNSHEYgI+KwzNBZrJ8LtQBsJT1DAoYj65gY5IdwwYbk3fj61XaM8LB4Nbpl9R3SABu+2OR2NcROlZX1CVWT/2UU3DKqEKve/I5+VNyknA9MTDmCEUnbAl2RkFgeQDVFxHDz/1GgAapbj2VVsWA7XJNZJuPTuNC3M=;
- Reply-to: obm-l@xxxxxxxxxxxxxx
- Sender: owner-obm-l@xxxxxxxxxxxxxx
SPAM: -------------------- Start SpamAssassin results ----------------------
SPAM: This mail is probably spam. The original message has been altered
SPAM: so you can recognise or block similar unwanted mail in future.
SPAM: See http://spamassassin.org/tag/ for more details.
SPAM:
SPAM: Content analysis details: (7.80 hits, 5 required)
SPAM: X_MAILING_LIST (-0.3 points) Found a X-Mailing-List header
SPAM: SPAM_PHRASE_00_01 (0.8 points) BODY: Spam phrases score is 00 to 01 (low)
SPAM: [score: 0]
SPAM: HTML_FONT_COLOR_BLUE (0.2 points) BODY: HTML font color is blue
SPAM: SPAM_REDIRECTOR (0.4 points) URI: Uses open redirection service
SPAM: FORGED_YAHOO_RCVD (1.4 points) 'From' yahoo.com does not match 'Received' headers
SPAM: RCVD_IN_ORBS (2.2 points) RBL: Received via a relay in orbs.dorkslayers.com
SPAM: [RBL check: found 28.37.190.206.orbs.dorkslayers.com., type: 68.178.232.99]
SPAM: RCVD_IN_OSIRUSOFT_COM (0.4 points) RBL: Received via a relay in relays.osirusoft.com
SPAM: [RBL check: found 28.37.190.206.relays.osirusoft.com.]
SPAM: X_OSIRU_OPEN_RELAY (2.7 points) RBL: DNSBL: sender is Confirmed Open Relay
SPAM:
SPAM: -------------------- End of SpamAssassin results ---------------------
--0-1342267679-1203822519=:99639
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
Ol=E1 Arthur=0AFa=E7a assim: a=3D 1+sqrt(2) =3D=3D> a^2 =3D 3+sqrt(8) e 1/a=
^2 =3D 3-sqrt(8) de forma que temos=0Aa^(2n) - 1/a^(2n) - 2 =3D (a^n - 1/a^=
n)^2. Resta somente provar que a^n - 1/a^n eh inteiro. Basta racionalizar =
e fazer a expansao binomial.=0A[]'s=0A Danilo.=0A=0A=0A----- Mensagem o=
riginal ----=0ADe: Artur Costa Steiner <artur.steiner@xxxxxxxxxx>=0APara: "=
obm-l@xxxxxxxxxxxxxx" <obm-l@xxxxxxxxxxxxxx>=0AEnviadas: Ter=E7a-feira, 19 =
de Fevereiro de 2008 15:34:30=0AAssunto: [obm-l] Provar que =E9 quadrado pe=
rfeito=0A=0A=0AGostaria que algu=E9m desse alguma sugest=E3o para isto:=0A =
=0AMostre que, para todo n =EDmpar positivo, (3 + raiz(8))^n + (3 - raiz(8)=
)^n - 2 eh um quadrado perfeito.=0A =0AAbracos=0AArtur=0A=0A=0A Abra=
sua conta no Yahoo! Mail, o =FAnico sem limite de espa=E7o para armazename=
nto!=0Ahttp://br.mail.yahoo.com/
--0-1342267679-1203822519=:99639
Content-Type: text/html; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
<html><head><style type=3D"text/css"><!-- DIV {margin:0px;} --></style></he=
ad><body><div style=3D"font-family:times new roman, new york, times, serif;=
font-size:12pt"><DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new roman=
, new york, times, serif">Ol=E1 Arthur</DIV>=0A<DIV style=3D"FONT-SIZE: 12p=
t; FONT-FAMILY: times new roman, new york, times, serif">Fa=E7a assim: a=3D=
1+sqrt(2) =3D=3D> a^2 =3D 3+sqrt(8) e 1/a^2 =3D 3-sqrt(8) de forma que =
temos</DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new roman, =
new york, times, serif">a^(2n) - 1/a^(2n) - 2 =3D (a^n - 1/a^n)^2. Res=
ta somente provar que a^n - 1/a^n eh inteiro. Basta racionalizar=
e fazer a expansao binomial.</DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; F=
ONT-FAMILY: times new roman, new york, times, serif">[]'s</DIV>=0A<DIV styl=
e=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new roman, new york, times, serif"=
> Danilo.<BR><BR></DIV>=0A<DIV style=3D"FONT-SIZE: =
12pt; FONT-FAMILY: times new roman, new york, times, serif">----- Mensagem =
original ----<BR>De: Artur Costa Steiner <artur.steiner@xxxxxxxxxx><B=
R>Para: "obm-l@xxxxxxxxxxxxxx" <obm-l@xxxxxxxxxxxxxx><BR>Enviadas: Te=
r=E7a-feira, 19 de Fevereiro de 2008 15:34:30<BR>Assunto: [obm-l] Provar qu=
e =E9 quadrado perfeito<BR><BR>=0A<DIV><FONT face=3DArial color=3D#0000ff s=
ize=3D2><SPAN class=3D983123218-19022008>Gostaria que algu=E9m desse alguma=
sugest=E3o para isto:</SPAN></FONT></DIV>=0A<DIV><FONT face=3DArial color=
=3D#0000ff size=3D2><SPAN class=3D983123218-19022008></SPAN></FONT> </=
DIV>=0A<DIV><FONT face=3DArial color=3D#0000ff size=3D2><SPAN class=3D98312=
3218-19022008>Mostre que, para todo n =EDmpar positivo, (3 + raiz(8))^n + (=
3 - raiz(8))^n - 2 eh um quadrado perfeito.</SPAN></FONT></DIV>=
=0A<DIV><FONT face=3DArial color=3D#0000ff size=3D2><SPAN class=3D983123218=
-19022008></SPAN></FONT> </DIV>=0A<DIV><FONT face=3DArial color=3D#000=
0ff size=3D2><SPAN class=3D983123218-19022008>Abracos</SPAN></FONT></DIV>=
=0A<DIV><FONT face=3DArial color=3D#0000ff size=3D2><SPAN class=3D983123218=
-19022008>Artur</SPAN></FONT></DIV></DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; =
FONT-FAMILY: times new roman, new york, times, serif"><BR></DIV></div><br>=
=0A=0A=0A <hr size=3D1>Abra sua conta no <a href=3D"http://br.rd.yahoo=
.com/mail/taglines/mail/*http://br.mail.yahoo.com/";>Yahoo! Mail</a>, o =FAn=
ico sem limite de espa=E7o para armazenamento! =0A</body></html>
--0-1342267679-1203822519=:99639--
=========================================================================
Instruções para entrar na lista, sair da lista e usar a lista em
http://www.mat.puc-rio.br/~obmlistas/obm-l.html
=========================================================================