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[SPAM] [obm-l] Composição de Funções
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Content-Type: text/plain;
charset="Windows-1252"
Content-Transfer-Encoding: quoted-printable
Ol=E1,
Dada a fun=E7=E3o f(x) =3D (2x + 1)/(x - 2), o valor se =
fof(2), =E9:=20
a) 1/4 b) 1/2 c) 2 d) 4 e) -4
O problema acima foi aplicado num exame de vestibular e o gabarito =
oficial apontava a alternativa C como correta.
=C9 f=E1cil ver que f(2) n=E3o existe, pois D(f) =3D R - {2}. Desse =
modo, ser=EDamos levados a concluir que o problema n=E3o apresenta =
alternativa correta, pois f(f(2)) n=E3o existe.
Por outro lado, f(f(x)) =3D x, donde f(f(2)) =3D 2. O que parece ter =
sido levado em considera=E7=E3o pelo examinador.
Pergunta: Onde est=E1 o erro?
Abra=E7os. =20
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Content-Type: text/html;
charset="Windows-1252"
Content-Transfer-Encoding: quoted-printable
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Dwindows-1252">
<META content=3D"MSHTML 6.00.6000.16587" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT color=3D#000080 size=3D2>Ol=E1,</FONT></DIV>
<DIV><FONT color=3D#000080 size=3D2></FONT> </DIV>
<DIV><FONT color=3D#000080 size=3D2></FONT> </DIV>
<DIV><FONT color=3D#000080><FONT=20
size=3D2> &nbs=
p; <FONT=20
color=3D#000000>D</FONT></FONT></FONT><FONT size=3D2>ada a fun=E7=E3o =
f(x) =3D (2x + 1)/(x=20
- 2), o valor se fof(2), =E9: <BR></FONT></DIV>
<DIV><FONT=20
size=3D2> &nbs=
p; a)=20
1/4 b) 1/2 c)=20
2 d)=20
4 e) -4</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>O problema acima foi aplicado num =
exame de=20
vestibular e o gabarito oficial apontava a alternativa C como=20
correta.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>=C9 f=E1cil ver que f(2) n=E3o existe, pois D(f) =3D =
R - {2}. Desse=20
modo, ser=EDamos levados a concluir que o problema n=E3o apresenta =
alternativa=20
correta, pois f(f(2)) n=E3o existe.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Por outro lado, f(f(x)) =3D x, donde f(f(2)) =3D 2. =
O que parece=20
ter sido levado em considera=E7=E3o pelo examinador.</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Pergunta: Onde est=E1 o erro?</FONT></DIV>
<DIV><FONT size=3D2></FONT> </DIV>
<DIV><FONT size=3D2>Abra=E7os. </FONT></DIV>
<DIV><FONT color=3D#000080 size=3D2></FONT> </DIV>
<DIV> </DIV></BODY></HTML>
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