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[SPAM] RES: [obm-l] polinomios

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a)Se houver duas ra=EDzes simetricas, entao a soma das raizes eh a =
terceira raiz, que, pelas relacoes de Girard, eh -(-3)/1 =3D 3. Assim, =
fazendo x =3D3, temos que, 27 - 27- 3k + 12 =3D 0 =3D=3D> k =3D 4.=20
=20
b) Se 1 for raiz, entao 1 -3 - k + 12 =3D 0 =3D> k =3D 10. Para achar as =
outras raizes, divida pelo binomio x - 10, obtendo uma equacao do 2o =
grau, e aplique Bhaskara.
=20
Artur

-----Mensagem original-----
De: owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx]Em =
nome de Ney Falcao
Enviada em: quinta-feira, 29 de novembro de 2007 20:41
Para: obm-l@xxxxxxxxxxxxxx
Assunto: [obm-l] polinomios


Poderiam me ajudar com esta:
=20
Considere a equa=E7=E3o x=B3-3x=B2-kx+12=3D0
a) Determine k de modo que haja duas ra=EDzes sim=E9tricas
b)Se 1 for raiz dessa equa=E7=E3o, quais s=E3o as outras ra=EDzes?
=20
Ney


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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META HTTP-EQUIV=3D"Content-Type" CONTENT=3D"text/html; =
charset=3Diso-8859-1">


<META content=3D"MSHTML 6.00.6000.16481" name=3DGENERATOR></HEAD>
<BODY>
<DIV><SPAN class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =
size=3D2>a)Se=20
houver duas ra=EDzes simetricas, entao a soma das raizes eh a terceira =
raiz, que,=20
pelas relacoes de Girard, eh -(-3)/1 =3D 3. </FONT></SPAN><SPAN=20
class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =
size=3D2>Assim, fazendo x=20
=3D3, temos que, 27 - 27- 3k + 12 =3D 0 =3D=3D&gt; k =3D =
4.&nbsp;</FONT></SPAN></DIV>
<DIV><SPAN class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =

size=3D2></FONT></SPAN>&nbsp;</DIV>
<DIV><SPAN class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =
size=3D2>b) Se=20
1 for raiz, entao 1 -3 - k + 12 =3D 0 =3D&gt; k =3D 10. Para achar as =
outras raizes,=20
divida pelo binomio x - 10, obtendo uma equacao do 2o grau,&nbsp;e =
aplique=20
Bhaskara.</FONT></SPAN></DIV>
<DIV><SPAN class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =

size=3D2></FONT></SPAN>&nbsp;</DIV>
<DIV><SPAN class=3D435181013-30112007><FONT face=3DArial color=3D#0000ff =

size=3D2>Artur</FONT></SPAN></DIV>
<BLOCKQUOTE dir=3Dltr style=3D"MARGIN-RIGHT: 0px">
  <DIV class=3DOutlookMessageHeader dir=3Dltr align=3Dleft><FONT =
face=3DTahoma=20
  size=3D2>-----Mensagem original-----<BR><B>De:</B> =
owner-obm-l@xxxxxxxxxxxxxx=20
  [mailto:owner-obm-l@xxxxxxxxxxxxxx]<B>Em nome de </B>Ney =
Falcao<BR><B>Enviada=20
  em:</B> quinta-feira, 29 de novembro de 2007 20:41<BR><B>Para:</B>=20
  obm-l@xxxxxxxxxxxxxx<BR><B>Assunto:</B> [obm-l]=20
polinomios<BR><BR></FONT></DIV>
  <DIV>Poderiam me ajudar com esta:</DIV>
  <DIV>&nbsp;</DIV>
  <DIV><EM><FONT color=3D#3333ff size=3D4>Considere a equa=E7=E3o=20
  x=B3-3x=B2-kx+12=3D0</FONT></EM></DIV>
  <DIV><EM><FONT color=3D#3333ff size=3D4>a) Determine k de modo que =
haja duas=20
  ra=EDzes sim=E9tricas</FONT></EM></DIV>
  <DIV><EM><FONT color=3D#3333ff size=3D4>b)Se 1 for raiz dessa =
equa=E7=E3o, quais s=E3o=20
  as outras ra=EDzes?</FONT></EM></DIV>
  <DIV>&nbsp;</DIV>
  <DIV>Ney</DIV></BLOCKQUOTE></BODY></HTML>

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