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[SPAM] Res: [obm-l] Autovalor
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- Subject: [SPAM] Res: [obm-l] Autovalor
- From: Klaus Ferraz <klausferraz@xxxxxxxxxxxx>
- Date: Sat, 17 Nov 2007 18:28:01 -0800 (PST)
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--0-1099090647-1195352881=:36645
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Ol=C3=A1 Leandro,=0A n=C3=A3o entendi porque vc sup=C3=B4s que P seri=
a a matriz colunas com os autovetores de A e S a matriz diagonal com os aut=
ovalores de A.=0AGrato.=0A=0A=0A----- Mensagem original ----=0ADe: LEANDRO =
L RECOVA <leandrorecova@xxxxxxx>=0APara: obm-l@xxxxxxxxxxxxxx=0AEnviadas: S=
exta-feira, 16 de Novembro de 2007 14:54:47=0AAssunto: RE: [obm-l] Autovalo=
r=0A=0AKlauss,=0A=0A=0ANa ultima pergunta, se voce supor a matriz quadrada,=
lembre que voce pode =0Adecompo-la na forma A=3DPSP^-1, onde P e a matriz =
cujas colunas contem os =0Aautovetores de A e S e a matriz diagonal com os =
autovalores de A. Segue =0Aimediato que o det(A)=3Ddet(S)=3Dproduto dos a=
utovalores de A. Agora o traco e =0Afacil de calcular e deixo pra voce.=0A=
=0ARegards,=0A=0ALeandro=0ALos Angeles, CA.=0A=0A=0A>From: Klaus Ferraz <kl=
ausferraz@xxxxxxxxxxxx>=0A>Reply-To: obm-l@xxxxxxxxxxxxxx=0A>To: obm-l@mat.=
puc-rio.br=0A>Subject: [obm-l] Autovalor=0A>Date: Tue, 13 Nov 2007 17:09:42=
-0800 (PST)=0A>=0A>Dado A E R n x n=0A>Se A=3D A^T ent=C3=83=C2=A3o todo a=
utovalor de A =C3=83=C2=A9 real=0A>Se A=3D-A^T ent=C3=83=C2=A3o todo autova=
lor de =C3=83=C2=A9 da forma ir, r E R=0A>=0A>Tamb=C3=83=C2=A9m como que eu=
mostro que o produto dos autovalores de uma matriz =C3=83=C2=A9 =0A>igual =
ao seu determinante e o tra=C3=83=C2=A7o igual a soma dos autovalores.=0A>G=
rato.=0A>=0A>=0A> Abra sua conta no Yahoo! Mail, o =C3=83=C2=BAnico se=
m limite de espa=C3=83=C2=A7o para =0A>armazenamento!=0A>http://br.mail.yah=
oo.com/=0A=0A=0A=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=0AInstru=C3=A7=C3=B5es para entrar na lista, sair da lista e u=
sar a lista em=0Ahttp://www.mat.puc-rio.br/~obmlistas/obm-l.html=0A=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=0A=0A=0A =
Abra sua conta no Yahoo! Mail, o =C3=BAnico sem limite de espa=C3=A7o pa=
ra armazenamento!=0Ahttp://br.mail.yahoo.com/
--0-1099090647-1195352881=:36645
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<html><head><style type=3D"text/css"><!-- DIV {margin:0px;} --></style></he=
ad><body><div style=3D"font-family:times new roman, new york, times, serif;=
font-size:12pt"><DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new roman=
, new york, times, serif">Ol=C3=A1 Leandro,</DIV>=0A<DIV style=3D"FONT-SIZE=
: 12pt; FONT-FAMILY: times new roman, new york, times, serif"> &=
nbsp; n=C3=A3o entendi porque vc sup=C3=B4s que P seria a=
matriz colunas com os autovetores de A e S a matriz diagonal com os autova=
lores de A.</DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new r=
oman, new york, times, serif">Grato.<BR><BR></DIV>=0A<DIV style=3D"FONT-SIZ=
E: 12pt; FONT-FAMILY: times new roman, new york, times, serif">----- Mensag=
em original ----<BR>De: LEANDRO L RECOVA <leandrorecova@xxxxxxx><BR>P=
ara: obm-l@xxxxxxxxxxxxxx<BR>Enviadas: Sexta-feira, 16 de Novembro de 2007 =
14:54:47<BR>Assunto: RE: [obm-l] Autovalor<BR><BR>Klauss,<BR><BR><BR>Na ult=
ima pergunta, se voce supor a matriz quadrada, lembre que voce pode <BR>dec=
ompo-la na forma A=3DPSP^-1, onde P e a matriz cujas colunas contem os <BR>=
autovetores de A e S e a matriz diagonal com os autovalores de A. Se=
gue <BR>imediato que o det(A)=3Ddet(S)=3Dproduto dos autovalores de A. Agor=
a o traco e <BR>facil de calcular e deixo pra voce.<BR><BR>Regards,<BR><BR>=
Leandro<BR>Los Angeles, CA.<BR><BR><BR>>From: Klaus Ferraz <<A href=
=3D"mailto:klausferraz@xxxxxxxxxxxx"; ymailto=3D"mailto:klausferraz@xxxxxxxx=
m.br">klausferraz@xxxxxxxxxxxx</A>><BR>>Reply-To: <A href=3D"mailto:o=
bm-l@xxxxxxxxxxxxxx"
ymailto=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A><BR>>To=
: <A href=3D"mailto:obm-l@xxxxxxxxxxxxxx"; ymailto=3D"mailto:obm-l@xxxxxxxxx=
io.br">obm-l@xxxxxxxxxxxxxx</A><BR>>Subject: [obm-l] Autovalor<BR>>Da=
te: Tue, 13 Nov 2007 17:09:42 -0800 (PST)<BR>><BR>>Dado A E R n x n<B=
R>>Se A=3D A^T ent=C3=83=C2=A3o todo autovalor de A =C3=83=C2=A9 real<BR=
>>Se A=3D-A^T ent=C3=83=C2=A3o todo autovalor de =C3=83=C2=A9 da forma i=
r, r E R<BR>><BR>>Tamb=C3=83=C2=A9m como que eu mostro que o produto =
dos autovalores de uma matriz =C3=83=C2=A9 <BR>>igual ao seu determinant=
e e o tra=C3=83=C2=A7o igual a soma dos autovalores.<BR>>Grato.<BR>><=
BR>><BR>> Abra sua conta no Yahoo! Mail, o =C3=83=
=C2=BAnico sem limite de espa=C3=83=C2=A7o para <BR>>armazenamento!<BR>&=
gt;<A href=3D"http://br.mail.yahoo.com/"; target=3D_blank>http://br.mail.yah=
oo.com/</A><BR><BR><BR>=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D<BR>Instru=C3=A7=C3=B5es para entrar na lista, sair da li=
sta e
usar a lista em<BR><A href=3D"http://www.mat.puc-rio.br/~obmlistas/obm-l.h=
tml" target=3D_blank>http://www.mat.puc-rio.br/~obmlistas/obm-l.html</A><BR=
>=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D<BR=
></DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times new roman, new =
york, times, serif"><BR></DIV></div><br>=0A=0A=0A <hr size=3D1>Abra su=
a conta no <a href=3D"http://br.rd.yahoo.com/mail/taglines/mail/*http://br.=
mail.yahoo.com/">Yahoo! Mail</a>, o =C3=BAnico sem limite de espa=C3=A7o pa=
ra armazenamento! =0A</body></html>
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