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[SPAM] [obm-l] OMU - 2007
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- Subject: [SPAM] [obm-l] OMU - 2007
- From: Klaus Ferraz <klausferraz@xxxxxxxxxxxx>
- Date: Tue, 23 Oct 2007 16:09:28 -0700 (PDT)
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--0-265618603-1193180968=:3907
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Ol=E1 na 2=BA questao na OMU desse ano http://www.obm.org.br/frameset-prova=
s.htm. =0AGostaria de saber por que que se definiu m=3Dmdc{k|a_k<>0} e tamb=
=E9m por que que "claramente 2pi/m =E9 um periodo de f:"? E que menor per=
=EDodo =E9 esse ? No final est=E1 k_p/2pi E Z num seria k*p/2pi E Z?=0ATamb=
=E9m nao entendi "equivalentemente, p deve ser um multiplo inteiro de 2pi/m=
."=0AEm resumo, num entendi quase nada.=0AGrato.=0A=0A=0A Abra sua con=
ta no Yahoo! Mail, o =FAnico sem limite de espa=E7o para armazenamento!=0Ah=
ttp://br.mail.yahoo.com/
--0-265618603-1193180968=:3907
Content-Type: text/html; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
<html><head><style type=3D"text/css"><!-- DIV {margin:0px;} --></style></he=
ad><body><div style=3D"font-family:times new roman, new york, times, serif;=
font-size:12pt"><DIV>=0A<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: times n=
ew roman, new york, times, serif">=0A<DIV>Ol=E1 na 2=BA questao na OMU dess=
e ano <A href=3D"http://www.obm.org.br/frameset-provas.htm"; target=3D_blank=
rel=3Dnofollow><FONT color=3D#800080>http://www.obm.org.br/frameset-provas=
.htm</FONT></A>. </DIV>=0A<DIV>Gostaria de saber por que que se definiu m=
=3Dmdc{k|a_k<>0} e tamb=E9m por que que "claramente 2pi/m =E9 um peri=
odo de f:"? E que menor per=EDodo =E9 esse ? No final est=E1 k_p/2pi E Z nu=
m seria k*p/2pi E Z?</DIV>=0A<DIV>Tamb=E9m nao entendi "equivalentemente, p=
deve ser um multiplo inteiro de 2pi/m."</DIV>=0A<DIV>Em resumo, num entend=
i quase nada.</DIV>=0A<DIV>Grato.</DIV></DIV></DIV></div><br>=0A=0A=0A =
Abra sua conta no <a href=3D"http://br.rd.yahoo.com/mail/taglines/mail/*ht=
tp://br.mail.yahoo.com/">Yahoo! Mail</a>, o =FAnico sem limite de espa=E7o =
para armazenamento! =0A</body></html>
--0-265618603-1193180968=:3907--
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