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[SPAM] RES: [obm-l] Intergral



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Marcelo, obrigado pela ajuda, mas e ai que ta o problema ta dando uma =
coisa
muito grande, ser=E1 que eu to fazendo algo de errado.

(ax+b)/(1-^sqrt(2)t+t^2) + (cx+d)/ (1+^sqrt(2)t+t^2) ve se e isso que =
tem
que ser feito.

=20

De: owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx] Em =
nome
de Marcelo Salhab Brogliato
Enviada em: segunda-feira, 22 de outubro de 2007 08:43
Para: obm-l@xxxxxxxxxxxxxx
Assunto: Re: [obm-l] Intergral

=20

Ol=E1 Marcus,

acredito que seja (2t^2) / (1 + t^4), certo?

1 + t^4 =3D 1 + 2t^2 + t^4 - 2t^2 =3D (1 + t^2)^2 - 2t^2 =3D (1 - =
sqrt(2)t +
t^2)*(1 + sqrt(2)t + t^2)

agora basta usar integracao por fracoes parciais :)=20


abra=E7os,
Salhab




On 10/22/07, Marcus <marcusaurelio80@xxxxxxxxx> wrote:=20

Algu=E9m sabe como resolver essa integral?

Integral de (2t^2)/1+t^4

=20


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<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>Marcelo, obrigado pela ajuda, mas e ai que ta o problema =
ta
dando uma coisa muito grande, ser=E1 que eu to fazendo algo de =
errado.<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
color:#1F497D'>(ax+b)/(1-^sqrt(2)t+t^2) + (cx+d)/ (1+^sqrt(2)t+t^2) ve =
se e
isso que tem que ser feito.<o:p></o:p></span></p>

<p class=3DMsoNormal><span =
style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";
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0cm 0cm 0cm'>

<p class=3DMsoNormal><b><span =
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b><span
style=3D'font-size:10.0pt;font-family:"Tahoma","sans-serif"'>
owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx] <b>Em =
nome de </b>Marcelo
Salhab Brogliato<br>
<b>Enviada em:</b> segunda-feira, 22 de outubro de 2007 08:43<br>
<b>Para:</b> obm-l@xxxxxxxxxxxxxx<br>
<b>Assunto:</b> Re: [obm-l] Intergral<o:p></o:p></span></p>

</div>

<p class=3DMsoNormal><o:p>&nbsp;</o:p></p>

<p class=3DMsoNormal style=3D'margin-bottom:12.0pt'>Ol=E1 Marcus,<br>
<br>
acredito que seja (2t^2) / (1 + t^4), certo?<br>
<br>
1 + t^4 =3D 1 + 2t^2 + t^4 - 2t^2 =3D (1 + t^2)^2 - 2t^2 =3D (1 - =
sqrt(2)t + t^2)*(1
+ sqrt(2)t + t^2)<br>
<br>
agora basta usar integracao por fracoes parciais :) <br>
<br>
<br>
abra=E7os,<br>
Salhab<br>
<br>
<br>
<o:p></o:p></p>

<div>

<p class=3DMsoNormal><span class=3Dgmailquote>On 10/22/07, <b>Marcus</b> =
&lt;<a
href=3D"mailto:marcusaurelio80@xxxxxxxxx";>marcusaurelio80@xxxxxxxxx</a>&g=
t;
wrote:</span> <o:p></o:p></p>

<div>

<div>

<p>Algu=E9m sabe como resolver essa integral?<o:p></o:p></p>

<p>Integral de (2t^2)/1+t^4<o:p></o:p></p>

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<p class=3DMsoNormal><o:p>&nbsp;</o:p></p>

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