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[SPAM] RES: [obm-l] duvida em espacial
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Obrigado pela ajuda
=20
_____ =20
De: owner-obm-l@mat.puc-rio.br [mailto:owner-obm-l@mat.puc-rio.br] Em =
nome
de Felipe Sardinha
Enviada em: quinta-feira, 28 de junho de 2007 18:24
Para: obm-l@mat.puc-rio.br
Assunto: Re: [obm-l] duvida em espacial
=20
Boa tarde Marcus,
=20
Sejam Sb, So e St valores correspondentes =E0 =E1rea da base, =E1rea da =
face
lateral da pir=E2mide e =E1rea total.
Sb =3D A1.(2p/3)/2 =3D (p.A1)/3
So =3D A2.(2p/3)/2 =3D (p.A2)/3
St =3D 3So + Sb =3D p.A2 + (p.A1)/3
...
St =3D p[(A1)/3 + A2]
=20
Abra=E7os
Felipe Marinho de Oliveira Sardinha
=20
=20
Marcus <marcusaurelio80@globo.com> escreveu:
Algu=E9m sabe como resolver este exerc=EDcio da prova da AFA? Obrigado
=20
A =E1rea total da pir=E2mide regular de ap=F3tema A2, onde A1 e 2p =
s=E3o,
respectivamente, ap=F3tema e per=EDmetro de sua base, =E9:
a) p(A1 + A2)
b) (A1 + A2)
c) 2p(A1 + A2)
d) p(A1 + )
=20
=20
=20
_____ =20
Novo Yahoo! Cad=EA? <http://yahoo.com.br/oqueeuganhocomisso%20> - =
Experimente
uma nova busca.=20
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<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DArial><span =
style=3D'font-size:
10.0pt;font-family:Arial;color:navy'>Obrigado pela =
ajuda<o:p></o:p></span></font></p>
<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DArial><span =
style=3D'font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
<div>
<div class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><font =
size=3D3
face=3D"Times New Roman"><span style=3D'font-size:12.0pt'>
<hr size=3D2 width=3D"100%" align=3Dcenter tabindex=3D-1>
</span></font></div>
<p class=3DMsoNormal><b><font size=3D2 face=3DTahoma><span =
style=3D'font-size:10.0pt;
font-family:Tahoma;font-weight:bold'>De:</span></font></b><font size=3D2
face=3DTahoma><span style=3D'font-size:10.0pt;font-family:Tahoma'> =
owner-<st1:PersonName
w:st=3D"on">obm-l@mat.puc-rio.br</st1:PersonName> =
[mailto:owner-<st1:PersonName
w:st=3D"on">obm-l@mat.puc-rio.br</st1:PersonName>] <b><span =
style=3D'font-weight:
bold'>Em nome de </span></b>Felipe Sardinha<br>
<b><span style=3D'font-weight:bold'>Enviada em:</span></b> quinta-feira, =
28 de
junho de 2007 18:24<br>
<b><span style=3D'font-weight:bold'>Para:</span></b> <st1:PersonName =
w:st=3D"on">obm-l@mat.puc-rio.br</st1:PersonName><br>
<b><span style=3D'font-weight:bold'>Assunto:</span></b> Re: [obm-l] =
duvida em
espacial</span></font><o:p></o:p></p>
</div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><o:p> </o:p></span></font></p>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><br>
Boa tarde Marcus,<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'> <o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>Sejam Sb, So e St valores correspondentes =E0 =E1rea da base, =
=E1rea da face
lateral da pir=E2mide e =E1rea total.<br>
<br>
Sb =3D A1.(2p/3)/2 =3D (p.A1)/3<br>
So =3D A2.(2p/3)/2 =3D (p.A2)/3<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>St =3D 3So + Sb =3D p.A2 + (p.A1)/3<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>...<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>St =3D p[(A1)/3 + A2]<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'> <o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>Abra=E7os<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>Felipe Marinho de Oliveira Sardinha<o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'> <o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'> <o:p></o:p></span></font></p>
</div>
<div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><br>
<b><i><span style=3D'font-weight:bold;font-style:italic'>Marcus
<marcusaurelio80@globo.com></span></i></b> =
escreveu:<o:p></o:p></span></font></p>
</div>
<blockquote style=3D'border:none;border-left:solid #1010FF =
1.5pt;padding:0cm 0cm 0cm 4.0pt;
margin-left:3.75pt;margin-top:5.0pt;margin-bottom:5.0pt'>
<div>
<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Algu=E9m sabe como resolver este exerc=EDcio da prova =
da AFA?
Obrigado<o:p></o:p></span></font></p>
</div>
<p class=3DMsoNormal style=3D'text-align:justify'><font size=3D3 =
face=3D"Arial Narrow"><span
style=3D'font-size:12.0pt;font-family:"Arial =
Narrow"'><o:p> </o:p></span></font></p>
<p class=3DMsoNormal style=3D'text-align:justify'><font size=3D3 =
face=3D"Arial Narrow"><span
style=3D'font-size:12.0pt;font-family:"Arial Narrow"'>A =E1rea total da =
pir=E2mide
regular de ap=F3tema A<sub>2</sub>, onde A<sub>1</sub> e 2p s=E3o, =
respectivamente,
ap=F3tema e per=EDmetro de sua base, =E9:<o:p></o:p></span></font></p>
<p class=3DMsoNormal =
style=3D'margin-left:1.0cm;text-align:justify;text-indent:
0cm;mso-list:l0 level2 lfo2'><![if !supportLists]><font size=3D1
face=3D"Zurich Cn BT"><span style=3D'font-size:9.0pt;font-family:"Zurich =
Cn BT"'><span
style=3D'mso-list:Ignore'>a)<font size=3D1 face=3D"Times New =
Roman"><span
style=3D'font:7.0pt "Times New =
Roman"'>  =
;
</span></font></span></span></font><![endif]><font face=3D"Arial =
Narrow"><span
style=3D'font-family:"Arial Narrow"'> p(A<sub>1 </sub>+ =
A<sub>2</sub>)<o:p></o:p></span></font></p>
<p class=3DMsoNormal =
style=3D'margin-left:1.0cm;text-align:justify;text-indent:
0cm;mso-list:l0 level2 lfo2'><![if !supportLists]><font size=3D1
face=3D"Zurich Cn BT"><span style=3D'font-size:9.0pt;font-family:"Zurich =
Cn BT"'><span
style=3D'mso-list:Ignore'>b)<font size=3D1 face=3D"Times New =
Roman"><span
style=3D'font:7.0pt "Times New =
Roman"'>  =
;
</span></font></span></span></font><![endif]><b><font face=3D"Arial =
Narrow"><span
style=3D'font-family:"Arial =
Narrow";position:relative;top:10.0pt;mso-text-raise:
-10.0pt;font-weight:bold'><img width=3D13 height=3D35 =
id=3D"_x0000_i1025"
src=3D"cid:image001.gif@01C7B9C7.A8F5A5D0"></span></font></b><font
face=3D"Arial Narrow"><span style=3D'font-family:"Arial =
Narrow"'>(A<sub>1 </sub>+ A<sub>2</sub>)<o:p></o:p></span></font></p>
<p class=3DMsoNormal =
style=3D'margin-left:1.0cm;text-align:justify;text-indent:
0cm;mso-list:l0 level2 lfo2'><![if !supportLists]><font size=3D1
face=3D"Zurich Cn BT"><span style=3D'font-size:9.0pt;font-family:"Zurich =
Cn BT"'><span
style=3D'mso-list:Ignore'>c)<font size=3D1 face=3D"Times New =
Roman"><span
style=3D'font:7.0pt "Times New =
Roman"'>  =
;
</span></font></span></span></font><![endif]><font face=3D"Arial =
Narrow"><span
style=3D'font-family:"Arial Narrow"'> 2p(A<sub>1 </sub>+ =
A<sub>2</sub>)<o:p></o:p></span></font></p>
<p class=3DMsoNormal =
style=3D'margin-left:1.0cm;text-align:justify;text-indent:
0cm;mso-list:l0 level2 lfo2'><![if !supportLists]><font size=3D1
face=3D"Zurich Cn BT"><span style=3D'font-size:9.0pt;font-family:"Zurich =
Cn BT"'><span
style=3D'mso-list:Ignore'>d)<font size=3D1 face=3D"Times New =
Roman"><span
style=3D'font:7.0pt "Times New =
Roman"'>  =
;
</span></font></span></span></font><![endif]><font face=3D"Arial =
Narrow"><span
style=3D'font-family:"Arial Narrow"'>p(A<sub>1 </sub>+ <span =
style=3D'position:
relative;top:10.0pt;mso-text-raise:-10.0pt'><img width=3D24 height=3D36
id=3D"_x0000_i1026" =
src=3D"cid:image002.gif@01C7B9C7.A8F5A5D0"></span>)<o:p></o:p></span></fo=
nt></p>
<div>
<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p> </o:p></span></font></p>
</div>
</blockquote>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><o:p> </o:p></span></font></p>
<p><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:12.0pt'>=A0 <o:p></o:p></span></font></p>
<div class=3DMsoNormal align=3Dcenter style=3D'text-align:center'><font =
size=3D3
face=3D"Times New Roman"><span style=3D'font-size:12.0pt'>
<hr size=3D1 width=3D"100%" align=3Dcenter>
</span></font></div>
<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'>Novo <a =
href=3D"http://yahoo.com.br/oqueeuganhocomisso%20">Yahoo! Cad=EA?</a>
- Experimente uma nova busca. <o:p></o:p></span></font></p>
</div>
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