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Re: [obm-l] Combinat�ria II
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Combinat�ria II
- From: Emanuel Valente <emanuelvalente@xxxxxxxxx>
- Date: Wed, 11 Apr 2007 18:27:23 -0300
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Bruna Carvalho escreveu:
> Se dispomos dos algarismos 2, 3, 4, 6 e 9, quantos n�meros de 4
> d�gitos distintos pode-se formar de modo que este seja m�ltiplo de 3?
>
> --
> Bjos,
> Bruna
Para ser m�ltiplo de 3, a soma dos algarismos deve ser m�ltiplo de 3.
Isso acontece com:
(2,3,4,6); (2,3,4,9);( 2,4,6,9) pois, a soma dos algarimos de cada grupo
vale 15, 18 e 21 respectivamente.
Cada grupo poder� formar 4! n�meros distintos. Portanto, o total de
n�meros distintos m�ltiplos de 3 ser� 3.4! , ou seja, 72.
Abra�os,
Emanuel Valente.
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