Re: [obm-l] trigonometria

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] trigonometria
From: ricardo.bioni@xxxxxxxxx
Date: Sun, 21 May 2006 16:26:59 -0300
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Fazendo 2npi/(2n+1) = y, sabemos que sen(y) = sen(pi - y), logo:
sen(2npi/(2n+1)) = sen(pi - 2npi/(2n+1))
= sen(pi/(2n+1))