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Re: [obm-l] Algebra
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Subject
: Re: [obm-l] Algebra
From
: Iuri <
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Date
: Thu, 27 Apr 2006 21:09:22 -0300
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(a+b)(a-b)=7
Como a+b > a-b, podemos ter a+b=4 e a-b=3 ou a+b=7 e a-b=1
Apenas o segundo sistema dá solucoes inteiras: a=4 e b=3.
Portanto, a-b=1 e a letra é B.
On 4/27/06,
Bruna Carvalho
<
bruna.carvalho.pink@gmail.com
> wrote:
Os números naturais a e b, com a>b, são tais que a^2-b^2=7. O valor de a-b é:
a)0 b)1 c)3 d)4 e)7
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