Re: [obm-l] analise limite

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] analise limite
From: Marcos Martinelli <mffmartinelli@xxxxxxxxx>
Date: Mon, 12 Dec 2005 20:17:56 -0200
DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=beta; d=gmail.com; h=received:message-id:date:from:to:subject:in-reply-to:mime-version:content-type:references; b=HvUARRQDJBNpdKOSHWwPJa3ohk4jfl8zau5rbjsoWku+KpzYiIWrtgeM0Gt/F15YXD0nZQshR3RLQm8jtQ16Zvj6oucTOCkb3FEE4iVNPo+G3bJUUGM/VXv50JAY5ulmbN32UaNSsMSlBEkjm0mejgNuT0NIeNZggtpURjKy18M=
In-Reply-To: <B64B42BFDD8C6A4FAF5463D8363FEB5804A9E106@smme0es01.mme.gov.br>
References: <B64B42BFDD8C6A4FAF5463D8363FEB5804A9E106@smme0es01.mme.gov.br>
Reply-To: obm-l@xxxxxxxxxxxxxx
Sender: owner-obm-l@xxxxxxxxxxxxxx

{[n^(1/n)] - 1}^n=e^{ln{[n^(1/n)] - 1}^n}}=e^{n*ln{[n^(1/n)] - 1}}. É fácil de demonstrar que

lim n^[1/n]=1. Logo o expoente tende pra -infinito e o termo todo tende pra zero.

References:
- RES: [obm-l] analise limite
  - From: Artur Costa Steiner