[obm-l] Ajuda em fatorial

[Sharon Guedes <sharongag@xxxxxxxxxxxx>]

Alguém poderia me ajudar nessas questões?

Reduzindo e simplificando a expressão ( n + 2 )! – (n – 3 )! , encontra-se :                                                               ( n + 1)!

1. – [(n + 2)] ²
2. (n + 2)! – (n + 3)!
3. [(n + 2)!] ²
4. [(n + 3)!] ²
5. – (n+2)!(n+3)!

 

(UFRGS) – A expressão (n +1)! – n! com n natural estritamente positivo vale:                              (n -1)! + n!

a) n² + n                                                                                                                                        1 + n

b) n² - n                                                                                                                                        1 + n                                             

c) n                                                                                                                                                1 + n

d) n² + n -1                                                                                                                                         2

e)     n²                                                                                                                                        1 + n

(PUCRS) Simplificando a expressão

4n ! + n! – (n + 1) ! obtém-se:                                                                                                   (n -1)!          n!

1. – n
2. 0
3. n
4. 2n
5. 3n

At. Sharon.

 

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