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Re: [obm-l] RELÓGIO DO IME
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] RELÓGIO DO IME
- From: "Ivan lopes" <lopesivan.del@xxxxxxxxx>
- Date: Thu, 11 Oct 2007 04:00:57 -0300
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82.5
82.5 = 60 + 22.5
82.5 = 60 + 45/2
sin(82.5) = sin(60 + 45/2)
= sin(60)cos(45/2) + sin(45/2)cos(60)
cos(45) = [cos(45/2)]^2 - [sin(45/2)]^2
cos(45) = [cos(45/2)]^2 - (1 - [cos(45/2)]^2 )
cos(45) = [cos(45/2)]^2 - 1 + [cos(45/2)]^2
cos(45) = 2cos(45/2) ^2 - 1
cos(45/2)^2 = ( cos(45) + 1)/2
cos(45/2) = sqrt[ ( cos(45) + 1)/2 ]
...
basta substituir ... agora eh com vc ... OK?
:)
[]'s
Ivan Carlos Da Silva Lopes
UFRJ/Cornell
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