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Re: [obm-l] SOMA DAS RAÍZES
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] SOMA DAS RAÍZES
- From: "Marcelo Salhab Brogliato" <msbrogli@xxxxxxxxx>
- Date: Wed, 12 Sep 2007 16:39:55 -0300
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- In-Reply-To: <JO9S41$61A7AD883E484134257D8274F4197DEB@bol.com.br>
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Olá Arkon,
sen3x = -sen2x
sen(3x) = sen(-2x) [pois o seno é uma funcao impar]
(i) 3x = -2x + 2kpi
ou
(ii) 3x = pi - (-2x) + 2kpi
(i): 5x = 2kpi ... x = 2kpi/5 ... raizes: 0, 2pi/5, 4pi/5
(ii): x = pi + 2kpi ... raizes: pi
logo: 0 + 2pi/5 + 4pi/5 + pi = 11pi/5
abraços,
Salhab
On 9/12/07, arkon <arkon@bol.com.br> wrote:
>
>
>
> Alguém pode resolver, por favor, esta:
>
>
>
> (AFA-97) A soma das raízes da equação sen 3x + sen 2x = 0 para 0 <= x < = pi
> é :
>
>
>
> a) 6.pi/5. b) 9.pi/5. c) 11.pi/5.
> d) 13.pi/5.
>
>
>
> DESDE JÁ MUITO OBRIGADO
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