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Re: [obm-l] Integral indefinida
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Integral indefinida
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Tue, 5 Jun 2007 17:53:59 -0300
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intrq(e^2y+e^y)dy
e^y=x^2
e^ydy=2xdx
dy=2dx/x
e a integral se resumea
xintrq(1+x^2)2dx/x
=2intrq(1+x^2) dx
recorrendo a seno e cosseno hiperbolico
cosh^2z-senh^2z=1
fdazendo a ransdformaçao x=senhz
dx=coshzdz
e a integral se resume a:
=2intsenhzcoshzdz=intsenh2zdz
=cosh2z/2
agora e so cvoltar
e^y=senhz^2
cosh2z=(e^2z+e^-2z)/2=
On 6/5/07, Anselmo Alves de Sousa <anselmo_rj@hotmail.com> wrote:
Oi colegas! Gostaria de ajuda em
Calcule integral de [ raiz (e^y) * raiz(1+e^y)]dy.
Ligue para os amigos com a Chamada de PC para PC - GRATUITO
Experimente já!