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Re: [obm-l] mediatriz
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] mediatriz
- From: "Marcelo Salhab Brogliato" <msbrogli@xxxxxxxxx>
- Date: Thu, 3 May 2007 17:03:55 -0300
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Ola Mario,
basta encontrar a equacao da reta perpendicular a reta BC e que passa
pelo ponto q vc encontrou!
o coeficiente angular da reta BC �: (-2-5)/(6-3) = -7/3
assim o coeficiente da reta q vc busca � 3/7..
y = 3x/7 + a
tem q passar pleo ponto (9/2, 3/2).. entao:
3/2 = 3(9/2)/7 + a
3/2 - 27/14 = a
a = 3/2 * (1 - 9/7) = 3/2 * (-2/7) = -3/7
assim: y = 3x/7 - 3/7 = 3/7 (x-1)
abracos,
Salhab
On 5/3/07, M�rio Pereira <marioappereira@terra.com.br> wrote:
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> Ol�!
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> Algu�m poderia dar uma dica?
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> Dado o tri�ngulo de v�rtices A (0,1), B (3,5) e C (6, -2), calcular a
> equa��o da mediatriz do segmento BC.
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> Bom, primeiro calculei o ponto m�dio entre BC, achando os pontos (9/2, 3/2),
> mas n�o sei como prosseguir.
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> Obrigado,
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> M�rio.
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>
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