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Re: [obm-l] 0^0 é solucao de eq.exponencial ?
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- Subject: Re: [obm-l] 0^0 é solucao de eq.exponencial ?
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Sun, 18 Mar 2007 22:14:33 -0300
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x=y^2
e tirando ln dos dois lados
2y*lny=y^2*lny
lny=0
y=1
y=0
y=2
On 3/15/07, Rafael <rfa1989@gmail.com> wrote:
Seja a equacao: x^( sqrt(x) ) = ( sqrt (x) )^x
Consegui resolver usando o artificio sqrt(x) = t. Dai encontrei que
x=0 e x=4 sao solucoes. A solucao x=1 so consigo encontrar "tentando"
mesmo.
A minha duvida principal é se vale a resposta x=0.
Tambem queria saber se tem um metodo melhor que o que usei de modo que
encontrasse a resposta x=1 sem ser por tentativa.
Muito Obrigado.
--------------------------------------------------
Rafael
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