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Re: [obm-l] UFCG - 2007

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Subject: Re: [obm-l] UFCG - 2007
From: "Marcelo Costa" <mat.moura@xxxxxxxxx>
Date: Mon, 22 Jan 2007 12:51:04 -0200
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Ajuda URGENTE!
Agarrei neste problema, por favor me ajudem.
Obrigado!

Em um triângulo ABC, tem-se que os ângulos ABC = ACB = 80º. Se P é um ponto sobre o lado AB tal que AP = BC, a medida do ângulo BPC é igual a:

References:
- [obm-l] UFCG - 2007
  - From: Rauryson Alves

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