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[obm-l] Re: [obm-l] Re:[obm-l] Triângulos

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Subject: [obm-l] Re: [obm-l] Re:[obm-l] Triângulos
From: "Thor" <thor@xxxxxxxxxxxxxx>
Date: Sun, 23 Jul 2006 19:10:53 -0300
References: <J19WLZ$40FCA60348DCB773CC6C8C136FD251F1@uol.com.br>
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6*(3)^1/2 é o lado do triangulo equilátero, a área será 27*(3)^1/2.

Cláudio Thor

----- Original Message -----

From: Giuliano (stuart)

To: obm-l

Sent: Thursday, June 22, 2006 2:58 PM

Subject: [obm-l] Re:[obm-l] Triângulos

Bom Dia!!!!!

A resposta é seis raiz de tręs, 6*(3)^1/2

Abraços,

Giuliano Pezzolo Giacaglia

(Stuart)

References:
- [obm-l] Re:[obm-l] Triângulos
  - From: Giuliano $stuart$

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