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[obm-l] Quadrilatero Circunscritivel
Oi, pessoal:
Um amigo me mandou este aqui, o qual nao me parece muito trivial...
Let ABCD be a quadrilateral with an inscribed circle with center O (all
sides of the quadrilateral are tangent to the circle). Assume that O does
not lie on AC. Construct a line through E on BD perpendicular to BD.
Then this line meets OA at R and OC at S. Show that |ER|=|ES|.
[]s,
Claudio.
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