[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: [obm-l] dificuldade

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] dificuldade
From: Augusto César Morgado <morgado@xxxxxxxxxxxxxxx>
Date: Sun, 24 Nov 2002 11:55:23 -0200
References: <195.1115e273.2b119a50@aol.com>
Reply-To: obm-l@xxxxxxxxxxxxxx
Sender: owner-obm-l@xxxxxxxxxxxxxxxxxxxxx
User-Agent: Mozilla/5.0 (Windows; U; Win98; en-US; rv:0.9.4.1) Gecko/20020508 Netscape6/6.2.3

Um polinomio eh f(x) = x^2. Nao tah faltando nada no enunciado?

Lltmdrtm@aol.com wrote:

195.1115e273.2b119a50@aol.com"> Sabendo que para todo x pertencente aos reais tem-se P(x) = P(-x-1). Determine
um polinômio f(x) tal que P(f(x)) = P(f(-x)).

References:
- [obm-l] dificuldade
  - From: Lltmdrtm

Prev by Date: Re: [obm-l] Matriz Inversa
Next by Date: [obm-l] ajuda
Prev by thread: [obm-l] dificuldade
Next by thread: Re: [obm-l] dificuldade
Index(es):
- Date
- Thread