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[SPAM] [obm-l] RES: [obm-l] PROGRESSÃO



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Solu=C3=A7=C3=A3o:
=20
a + ka + k^2 a + k^3 a =3D 360   ;   k^3 a =3D 9 ka   -->   k =3D 3   =
-->   a =3D 9=C2=BA
=20
Sds.,
AB!
=20


  _____ =20

De: owner-obm-l@xxxxxxxxxxxxxx [mailto:owner-obm-l@xxxxxxxxxxxxxx] Em =
nome de arkon@xxxxxxxxxx
Enviada em: sexta-feira, 27 de junho de 2008 22:59
Para: obm-l@xxxxxxxxxxxxxx
Assunto: [obm-l] PROGRESS=C3=83O=20


 =20

ALGU=C3=89M PODE RESOLVER, POR FAVOR

(UnB) Os quatro =C3=A2ngulos de um quadril=C3=A1tero est=C3=A3o em =
progress=C3=A3o geom=C3=A9trica e o =C3=BAltimo termo =C3=A9 9 vezes o =
segundo. Ent=C3=A3o o menor dos =C3=A2ngulos mede 9=C2=BA ?



DESDE J=C3=81 AGRADE=C3=87O

=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D =
Instru=EF=BF=BD=EF=BF=BDes para entrar na lista, sair da lista e usar a =
lista em http://www.mat.puc-rio.br/~obmlistas/obm-l.html =
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D


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=EF=BB=BF<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; charset=3Dutf-8">
<META content=3D"MSHTML 6.00.6000.16674" name=3DGENERATOR></HEAD>
<BODY>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN=20
class=3D843062703-28062008>Solu=C3=A7=C3=A3o:</SPAN></STRONG></DIV>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN=20
class=3D843062703-28062008></SPAN></STRONG>&nbsp;</DIV>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN class=3D843062703-28062008>a + =
ka + k^2 a +=20
k^3 a =3D 360&nbsp;&nbsp; ;&nbsp;&nbsp; k^3 a =3D 9 ka&nbsp;&nbsp;=20
--&gt;&nbsp;&nbsp; k =3D 3&nbsp;&nbsp; --&gt;&nbsp;&nbsp; a =3D=20
9=C2=BA</SPAN></STRONG></DIV>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN=20
class=3D843062703-28062008></SPAN></STRONG>&nbsp;</DIV>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN=20
class=3D843062703-28062008>Sds.,</SPAN></STRONG></DIV>
<DIV dir=3Dltr align=3Dleft><STRONG><SPAN=20
class=3D843062703-28062008>AB!</SPAN></STRONG></DIV>
<DIV>&nbsp;</DIV><BR>
<BLOCKQUOTE=20
style=3D"PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px =
solid; MARGIN-RIGHT: 0px">
  <DIV class=3DOutlookMessageHeader lang=3Dpt-br dir=3Dltr align=3Dleft>
  <HR tabIndex=3D-1>
  <FONT face=3DTahoma size=3D2><B>De:</B> owner-obm-l@xxxxxxxxxxxxxx=20
  [mailto:owner-obm-l@xxxxxxxxxxxxxx] <B>Em nome de=20
  </B>arkon@xxxxxxxxxx<BR><B>Enviada em:</B> sexta-feira, 27 de junho de =
2008=20
  22:59<BR><B>Para:</B> obm-l@xxxxxxxxxxxxxx<BR><B>Assunto:</B> [obm-l]=20
  PROGRESS=C3=83O <BR></FONT><BR></DIV>
  <DIV></DIV>&nbsp;=20
  <P><STRONG>ALGU=C3=89M PODE RESOLVER, POR FAVOR<BR><BR>(UnB) Os quatro =
=C3=A2ngulos de=20
  um quadril=C3=A1tero est=C3=A3o em progress=C3=A3o geom=C3=A9trica e o =
=C3=BAltimo termo =C3=A9 9 vezes o=20
  segundo. Ent=C3=A3o o menor dos =C3=A2ngulos mede 9=C2=BA =
?<BR><BR><BR><BR>DESDE J=C3=81=20
  =
AGRADE=C3=87O</STRONG></P>=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=20
  Instru=EF=BF=BD=EF=BF=BDes para entrar na lista, sair da lista e usar =
a lista em=20
  http://www.mat.puc-rio.br/~obmlistas/obm-l.html=20
  =
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D</BL=
OCKQUOTE></BODY></HTML>

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