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[SPAM] RE: [obm-l] distribuição normal

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--_920ec7bb-e110-452e-8237-cde6d62ace6d_
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=20
Lu,
=20
Pelo teorema central do limite, a m=E9dia amostral Xbarra segue uma distrib=
ui=E7=E3o normal
com a m=E9dia da popula=E7=E3o e vari=E2ncia da popula=E7=E3o dividido po n=
. ( onde n =E9 o tamanho da amostra).
=20
No seu caso Xbarra~N(2, 2/10).
=20
Agora voc=EA deve padronizar para obter as probabilidades desejadas.
=20
Em seguida eh s=F3 procurar uma tabela da normal (0,1) e proceder como usua=
lmente.
=20
Abs
=20
=20
=20
Fran=20


Date: Thu, 19 Jun 2008 09:24:27 -0300Subject: [obm-l] distribui=E7=E3o norm=
alFrom: lucianarodriggues@xxxxxxxxxxxx: obm-l@xxxxxxxxxxxxxx


Ol=E1 amigos,
Algu=E9m poderia me explicar como fazer esta quest=E3o?
=20
Coleta-se uma amostra de 10 observa=E7=F5es independentes de uma N(2, 2). D=
etermine a probabilidade da m=E9dia amostral:
a) Ser inferior a 1.
b) Ser superior a 2,5.
c) Estar entre 0 e 2.
Abra=E7os, Lu
=20
_________________________________________________________________
Conhe=E7a o Windows Live Spaces, a rede de relacionamentos do Messenger!
http://www.amigosdomessenger.com.br/=

--_920ec7bb-e110-452e-8237-cde6d62ace6d_
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Content-Transfer-Encoding: quoted-printable

<html>
<head>
<style>
.hmmessage P
{
margin:0px;
padding:0px
}
body.hmmessage
{
FONT-SIZE: 10pt;
FONT-FAMILY:Tahoma
}
</style>
</head>
<body class=3D'hmmessage'>&nbsp;<BR>
Lu,<BR>
&nbsp;<BR>
Pelo teorema central do limite, a m=E9dia amostral&nbsp;Xbarra segue uma di=
stribui=E7=E3o normal<BR>
com a m=E9dia da popula=E7=E3o e vari=E2ncia da popula=E7=E3o dividido po n=
. ( onde n =E9 o tamanho da amostra).<BR>
&nbsp;<BR>
No seu caso Xbarra~N(2, 2/10).<BR>
&nbsp;<BR>
Agora voc=EA deve padronizar para obter as probabilidades desejadas.<BR>
&nbsp;<BR>
Em seguida eh s=F3 procurar uma tabela da normal (0,1) e proceder como usua=
lmente.<BR>
&nbsp;<BR>
Abs<BR>
&nbsp;<BR>
&nbsp;<BR>
&nbsp;<BR>
Fran&nbsp;<BR><BR><BR>
<BLOCKQUOTE>
<HR id=3DEC_stopSpelling>
Date: Thu, 19 Jun 2008 09:24:27 -0300<BR>Subject: [obm-l] distribui=E7=E3o =
normal<BR>From: lucianarodriggues@xxxxxxxxxx<BR>To: obm-l@xxxxxxxxxxxxxx<BR=
><BR>
<DIV style=3D"FONT-SIZE: 12px; FONT-FAMILY: verdana, arial">
<DIV><FONT face=3DCMSS10 size=3D3>
<P align=3Dleft>Ol=E1 amigos,</P>
<P align=3Dleft>Algu=E9m poderia me explicar como fazer esta quest=E3o?</P>
<P align=3Dleft>&nbsp;</P>
<P align=3Dleft>Coleta-se uma amostra de 10 observa=E7=F5es independentes d=
e uma </FONT><FONT face=3DCMMI10 size=3D3>N</FONT><FONT face=3DCMR10 size=
=3D3>(2</FONT><FONT face=3DCMMI10 size=3D3>, </FONT><FONT face=3DCMR10 size=
=3D3>2)</FONT><FONT face=3DCMSS10 size=3D3>. Determine a probabilidade da m=
=E9dia amostral:</P>
<P align=3Dleft>a) Ser inferior a 1.</P>
<P align=3Dleft>b) Ser superior a 2,5.</P>
c) Estar entre 0 e 2.<BR>
Abra=E7os, Lu<BR>
&nbsp;<BR></FONT></DIV></DIV></BLOCKQUOTE><br /><hr />Conhe=E7a j=E1 o Wind=
ows Live Spaces, o site de relacionamentos do Messenger! <a href=3D'http://=
www.amigosdomessenger.com.br' target=3D'_new'>Crie j=E1 o seu!</a></body>
</html>=

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