[SPAM] Re: [obm-l] En: Trigonometria

["saulo nilson" <saulo.nilson@xxxxxxxxx>]

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ou de outro jeito
f(x)=3Df(x-p)
f(ax)=3Df(ax-p)
h(x)=3Dm+nf(ax-p)
h(x+p=B4)=3Dm+nf(ax+ap=B4-p)
ap=B4=3Dp
p=B4=3Dp/absa



On 6/16/08, Paulo Mello <pmello97@xxxxxxxxxxxx> wrote:
>
> Bom dia, pesoal.  Desejo ajuda para provar a seguinte proposi=E7=E3o:
> Dado f(x) , fun=E7=E3o peri=F3dica de per=EDodo p, ent=E3o a fun=E7=E3o d=
efinida por
> h(x)=3Dm+nf(ax+b) =E9 peri=F3dica e seu per=EDodo =E9 : p=3Dp/abs(a).
> abs(a)=3Dm=F3dulo de a.
>
> Obrigado pela for=E7a.
>
> Paulo Mello
>
>
>
> ------------------------------
> Abra sua conta no Yahoo! Mail<http://br.rd.yahoo.com/mail/taglines/mail/*=
http://br.mail.yahoo.com/>,
> o =FAnico sem limite de espa=E7o para armazenamento!
>
>
>
> ---------- Forwarded message ----------
> From: Paulo Mello <pmello97@xxxxxxxxxxxx>
> To: obm-l@xxxxxxxxxxxxxx
> Date: Sat, 14 Jun 2008 09:10:53 -0300 (ART)
> Subject: Trigonometria
> Bom dia, pesoal.
>
> Desejo ajuda(orienta=E7=E3o) para provar a seguinte proposi=E7=E3o:
> Dado f(x) , fun=E7=E3o peri=F3dica de per=EDodo p, ent=E3o a fun=E7=E3o d=
efinida por
> h(x)=3Dm+nf(ax+b) =E9 peri=F3dica e seu per=EDodo =E9 : p=3Dp/abs(a).
> abs(a)=3Dm=F3dulo de a.
>
> Obrigado pela for=E7a.
>
> Paulo Mello
>
> ------------------------------
> Abra sua conta no Yahoo! Mail<http://br.rd.yahoo.com/mail/taglines/mail/*=
http://br.mail.yahoo.com/>,
> o =FAnico sem limite de espa=E7o para armazenamento!
>
>
>

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<div>ou de outro jeito</div>
<div>f(x)=3Df(x-p)</div>
<div>f(ax)=3Df(ax-p)</div>
<div>h(x)=3Dm+nf(ax-p)</div>
<div>h(x+p=B4)=3Dm+nf(ax+ap=B4-p)</div>
<div>ap=B4=3Dp</div>
<div>p=B4=3Dp/absa</div>
<div><br><br>&nbsp;</div>
<div><span class=3D"gmail_quote">On 6/16/08, <b class=3D"gmail_sendername">=
Paulo Mello</b> &lt;<a href=3D"mailto:pmello97@xxxxxxxxxxxx";>pmello97@yahoo=
.com.br</a>&gt; wrote:</span>=20
<blockquote class=3D"gmail_quote" style=3D"PADDING-LEFT: 1ex; MARGIN: 0px 0=
px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">
<form action=3D"http://address.mail.yahoo.com/yab/br?v=3DYM&amp;.rand=3D807=
69&amp;A=3Dm&amp;simp=3D1" method=3D"post">Bom dia, pesoal.</form>
<div>
<div>
<div>Desejo ajuda para provar a seguinte proposi=E7=E3o:</div>
<div>Dado f(x) , fun=E7=E3o peri=F3dica de per=EDodo p, ent=E3o a fun=E7=E3=
o definida por </div>
<div>h(x)=3Dm+nf(ax+b) =E9 peri=F3dica e seu per=EDodo =E9 : p=3Dp/abs(a).<=
/div>
<div>abs(a)=3Dm=F3dulo de a.</div>
<div>&nbsp;</div>
<div>Obrigado pela for=E7a.</div>
<div>&nbsp;</div><span class=3D"sg">
<div>Paulo Mello</div></span><br>&nbsp;</div></div><span class=3D"ad">
<p>
<hr size=3D"1">
Abra sua conta no <a onclick=3D"return top.js.OpenExtLink(window,event,this=
)" href=3D"http://br.rd.yahoo.com/mail/taglines/mail/*http://br.mail.yahoo.=
com/" target=3D"_blank">Yahoo! Mail</a>, o =FAnico sem limite de espa=E7o p=
ara armazenamento!=20
<p></p></p></span><br><br>---------- Forwarded message ----------<br>From:&=
nbsp;Paulo Mello &lt;<a href=3D"mailto:pmello97@xxxxxxxxxxxx";>pmello97@yaho=
o.com.br</a>&gt;<br>To:&nbsp;<a href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@=
mat.puc-rio.br</a><br>
Date:&nbsp;Sat, 14 Jun 2008 09:10:53 -0300 (ART)<br>Subject:&nbsp;Trigonome=
tria<br>
<div>Bom dia, pesoal.</div>
<div>&nbsp;</div>
<div>Desejo ajuda(orienta=E7=E3o) para provar a seguinte proposi=E7=E3o:</d=
iv>
<div>Dado f(x) , fun=E7=E3o peri=F3dica de per=EDodo p, ent=E3o a fun=E7=E3=
o definida por h(x)=3Dm+nf(ax+b) =E9 peri=F3dica e seu per=EDodo =E9 : p=3D=
p/abs(a).</div>
<div>abs(a)=3Dm=F3dulo de a.</div>
<div>&nbsp;</div>
<div>Obrigado pela for=E7a.</div>
<div>&nbsp;</div>
<div>Paulo Mello</div>
<p>
<hr size=3D"1">
Abra sua conta no <a onclick=3D"return top.js.OpenExtLink(window,event,this=
)" href=3D"http://br.rd.yahoo.com/mail/taglines/mail/*http://br.mail.yahoo.=
com/" target=3D"_blank">Yahoo! Mail</a>, o =FAnico sem limite de espa=E7o p=
ara armazenamento!=20
<p></p><br></p></blockquote></div><br>

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