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[SPAM] Re: [obm-l] Congruencias



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Ol=E1,
Acho que o enunciado est=E1 errado.
Se eu entendi direito, fazendo n=3D3 ou n=3D5 n=E3o da certo...
Abra=E7os.
  ----- Original Message -----=20
  From: Igor Battazza=20
  To: obm-l@xxxxxxxxxxxxxx=20
  Sent: Sunday, February 10, 2008 8:55 AM
  Subject: [obm-l] Congruencias


  Bom dia!

  Estava resolvendo uns problemihas de congruencia e enrosquei nesse =
aqui:

  "Prove que n divide 1^n + 2^(n-1) + ... + (n-1)^(n-1) se n =E9 =
=EDmpar."

  Acho que n=E3o estou conseguindo compreender o enunciado (se isso ja n =
=E9 proposital por quem o elaborou)

  Qualquer ajudda =E9 bem vinda!

  Obrigado,
  Igor F. Carboni Battazza.

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2900.3243" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Ol=E1,</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Acho que o enunciado est=E1 =
errado.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Se eu entendi direito, fazendo n=3D3 ou =
n=3D5 n=E3o da=20
certo...</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Abra=E7os.</FONT></DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  <DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV=20
  style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
  <A title=3Dbattazza@xxxxxxxxx href=3D"mailto:battazza@xxxxxxxxx";>Igor =
Battazza</A>=20
  </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@xxxxxxxxxxxxxx=20
  href=3D"mailto:obm-l@xxxxxxxxxxxxxx";>obm-l@xxxxxxxxxxxxxx</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Sunday, February 10, 2008 =
8:55=20
  AM</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Subject:</B> [obm-l] =
Congruencias</DIV>
  <DIV><BR></DIV>Bom dia!<BR><BR>Estava resolvendo uns problemihas de=20
  congruencia e enrosquei nesse aqui:<BR><BR>"Prove que n divide 1^n + =
2^(n-1) +=20
  ... + (n-1)^(n-1) se n =E9 =EDmpar."<BR><BR>Acho que n=E3o estou =
conseguindo=20
  compreender o enunciado (se isso ja n =E9 proposital por quem o=20
  elaborou)<BR><BR>Qualquer ajudda =E9 bem =
vinda!<BR><BR>Obrigado,<BR>Igor F.=20
  Carboni Battazza.<BR></BLOCKQUOTE></BODY></HTML>

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