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[SPAM] Re: [obm-l] Primeira dúvida



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i = e^[i(PI/2 + K.PI)], K pertencente a Z, logo
   
  i^i = e^[-(PI/2 + K.PI)], K pertencente a Z
   
  i^i tem infinitos valores Reais, em particular,
  quando k = 0, i^i = e^(-PI/2), conforme já foi mostrado.
   
  [ ]´s
  Angelo
   
  Sérgio Martins da Silva <sms.sergio@xxxxxxxxx> escreveu:
          Caros participantes da lista,
   
  Gosto de matemática e estou chegando agora à lista. Eis minha primeira dúvida:
   
  Quanto é i ^ i ? Significa alguma coisa?
   
  Sérgio


       
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<div>i = e^[i(PI/2 + K.PI)], K pertencente a Z, logo</div>  <div>&nbsp;</div>  <div>i^i = e^[-(PI/2 + K.PI)], K pertencente a Z</div>  <div>&nbsp;</div>  <div>i^i tem infinitos valores Reais, em particular,</div>  <div>quando k = 0, i^i = e^(-PI/2), conforme já foi mostrado.</div>  <div>&nbsp;</div>  <div>[ ]´s</div>  <div>Angelo</div>  <div>&nbsp;</div>  <div><B><I>Sérgio Martins da Silva &lt;sms.sergio@xxxxxxxxx&gt;</I></B> escreveu:</div>  <BLOCKQUOTE class=replbq style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #1010ff 2px solid">  <META content="MSHTML 6.00.2800.1601" name=GENERATOR>  <STYLE></STYLE>    <DIV><FONT face=Arial size=2>Caros participantes da lista,</FONT></DIV>  <DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>  <DIV><FONT face=Arial size=2>Gosto de matemática e estou chegando agora à lista. Eis minha primeira dúvida:</FONT></DIV>  <DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>  <DIV><FONT face=Arial size=2>Quanto é i ^ i ? Significa alguma
 coisa?</FONT></DIV>  <DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>  <DIV><FONT face=Arial size=2>Sérgio</FONT></DIV></BLOCKQUOTE><BR><p>&#32;


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