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[SPAM] [obm-l] En: [obm-l] Só pega no tranco!!

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Ainda fiquei sem em entender sua nota=E7=E3o...
----- Original Message -----=20
From: alexmay nunes soares=20
To: obm-l@xxxxxxxxxxxxxx=20
Sent: Sunday, November 11, 2007 2:05 AM
Subject: Re: [obm-l] S=F3 pega no tranco!!


certamente vc usou o fato de que xd+xa=3Dxb+xc, o mesmo valendo pra y, =
neste caso vc considerou implicitamente que ad e bc s=E3o diagonais, =
tente ver outras formas de combina=E7=E3o entre os v=E9rtices para =
diagonais.

araketu <araketu@xxxxxxxxxxxx> escreveu:=20
  Sabendo que A(1,-1),B(5,1) e C(6,4) s=E3o v=E9rtices de um =
paralelogramo, determinar o quarto v=E9rtice de cada um dos tr=EAs =
paralelogramos poss=EDveis de serem formados.

  Resp.: (2,2), (0,4) e (10,6)

  Minha d=FAvida: eu concegui alcan=E7ar o ponto (2,2), minhas outras =
tentativas recairam no mesmo resultado por mim encontrado. Logo, pe=E7o =
ajuda te=F3rica para encontrar as outras duas poss=EDveis formas de =
constru=E7=E3o do paralelogramo.=20

  Agrade=E7o, como sempre a lista
  Abra=E7os!




-------------------------------------------------------------------------=
-------
Abra sua conta no Yahoo! Mail, o =FAnico sem limite de espa=E7o para =
armazenamento!=20

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META content=3D"text/html; charset=3Diso-8859-1" =
http-equiv=3DContent-Type>
<META content=3D"MSHTML 5.00.2614.3500" name=3DGENERATOR></HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Ainda fiquei sem em entender sua=20
nota=E7=E3o...</FONT></DIV>
<DIV style=3D"FONT: 10pt arial">----- Original Message -----=20
<DIV style=3D"BACKGROUND: #e4e4e4; font-color: black"><B>From:</B> <A=20
href=3D"mailto:alexmaynunes@xxxxxxxxxxxx"; =
title=3Dalexmaynunes@xxxxxxxxxxxx>alexmay=20
nunes soares</A> </DIV>
<DIV><B>To:</B> <A href=3D"mailto:obm-l@xxxxxxxxxxxxxx"=20
title=3Dobm-l@xxxxxxxxxxxxxx>obm-l@xxxxxxxxxxxxxx</A> </DIV>
<DIV><B>Sent:</B> Sunday, November 11, 2007 2:05 AM</DIV>
<DIV><B>Subject:</B> Re: [obm-l] S=F3 pega no tranco!!</DIV></DIV>
<DIV><BR></DIV>certamente vc usou o fato de que xd+xa=3Dxb+xc, o mesmo =
valendo pra=20
y, neste caso vc considerou implicitamente que ad e bc s=E3o diagonais, =
tente ver=20
outras formas de combina=E7=E3o entre os v=E9rtices para=20
diagonais.<BR><BR><B><I>araketu &lt;<A=20
href=3D"mailto:araketu@xxxxxxxxxxxx";>araketu@xxxxxxxxxxxx</A>&gt;</I></B>=
=20
escreveu:=20
<BLOCKQUOTE class=3Dreplbq=20
style=3D"BORDER-LEFT: #1010ff 2px solid; MARGIN-LEFT: 5px; PADDING-LEFT: =
5px">
  <META content=3D"MSHTML 5.00.2614.3500" name=3DGENERATOR>
  <STYLE></STYLE>

  <DIV><FONT face=3DArial size=3D2>Sabendo que A(1,-1),B(5,1) e C(6,4) =
s=E3o v=E9rtices=20
  de um paralelogramo, determinar o quarto v=E9rtice de cada um dos =
tr=EAs=20
  paralelogramos poss=EDveis de serem formados.</FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Resp.: (2,2), (0,4) e =
(10,6)</FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Minha d=FAvida: eu concegui =
alcan=E7ar o ponto (2,2),=20
  minhas outras tentativas recairam no mesmo resultado por mim =
encontrado. Logo,=20
  pe=E7o ajuda te=F3rica para encontrar as outras duas poss=EDveis =
formas de=20
  constru=E7=E3o do paralelogramo. </FONT></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>Agrade=E7o, como sempre a =
lista</FONT></DIV>
  <DIV><FONT face=3DArial =
size=3D2>Abra=E7os!</FONT></DIV></BLOCKQUOTE><BR>
<P>
<HR SIZE=3D1>
Abra sua conta no <A=20
href=3D"http://br.rd.yahoo.com/mail/taglines/mail/*http://br.mail.yahoo.c=
om/">Yahoo!=20
Mail</A>, o =FAnico sem limite de espa=E7o para armazenamento! =
</BODY></HTML>

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