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Re: [obm-l] Exponecial
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Exponecial
- From: "Emanuel Valente" <emanuelvalente@xxxxxxxxx>
- Date: Sat, 10 Nov 2007 20:55:49 -0300
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Aline, coloquei logarítimos dos dois lados pra facilitar. Tem o gabarito aí?
(7-3x) ^ (1-x)/(1+x) = 1
log[(7-3x) ^ (1-x)/(1+x)] = log1
(1-x)/(1+x) * log(7-3x) = 0
(1-x) * log(7-3x) = 0 (dividi a linha de cima por 1+x)
(1-x) = 0 => x = 1
ou
log(7-3x) = 0 => 7-3x=1 => 3x=6 => x = 2.
Solução: 1 e 2
On Nov 9, 2007 9:21 PM, Aline <oliveira-aline1983@xxxxxxxxxx> wrote:
>
>
>
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> Nesta questão , só tô encontrado 1 como resposta e o gabarito tá dizendo que
> tem duas soluções reais..
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> Quantas soluções, em números reais, a equação
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> (7-3x)^(1-x)/(1+x) =1
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> admite?
>
> A) 0
>
> B) 1
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> C) 2
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> D) 3
>
> E) 4
>
>
>
> Aline
>
>
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