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Re: [obm-l] RAÍZES INTEIRAS
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] RAÍZES INTEIRAS
- From: "Ivan lopes" <lopesivan.del@xxxxxxxxx>
- Date: Thu, 11 Oct 2007 17:34:31 -0300
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i) solucao para quem viu ....
p(x) = x^3 -2x^2 -5x +6
-> x^3 - x^2 - x^2 - 6x + x +6
-> x^3 - x^2 - 6x - x^2 + x +6
-> x^3 - x^2 -6x - (x^2 -x -6)
-> (x^2 - x - 6)x - (x^2 - x -6)
-> (x^2 - x - 6)(x-1)
-> (x^2 - 3x + 2x -6)(x-1)
-> [(x -3)x + 2(x -3)](x-1)
-> (x -3)(x + 2)(x-1)
pronto ....
ii) cara ... sao coeficientes inteiros ... neh
entao chuta x = 1
p(1) = 1 -2 -5 +6 = 0
eh raiz
....
baixamos a ordem da equacao ...
Briot-Ruffini
|3 -2 -5 6
1|1 -3 -2 0
x^2 - x - 6
x = 3 e x = -2
--
[ ]'s
Ivan Carlos Da Silva Lopes
Engenheiro Eletronico e Computacao - UFRJ
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